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Anuta_ua [19.1K]
3 years ago
15

Last question!!!!!explain if posible ​

Mathematics
1 answer:
emmasim [6.3K]3 years ago
6 0

Answer:

<h2><em><u><</u></em><em><u>ABT</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>43</u></em><em><u>°</u></em></h2><h2><em><u><</u></em><em><u>TBC</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>43</u></em><em><u>°</u></em></h2>

Step-by-step explanation:

<em><u>Given</u></em><em><u>, </u></em>

Line BT is the bisector of <ABC

<em><u>So</u></em><em><u>,</u></em>

3x + 13 = 5x - 7

=> 13 + 7 = 5x - 3x

=> 20 = 2x

=  > x =  \frac{20}{2}

=> x = 10

<em><u>As</u></em><em><u>,</u></em><em><u> </u></em>

We got the value of <em><u>x = 10</u></em>

<em><u>Therefore</u></em><em><u>, </u></em>

<em><u><ABT</u></em> = 3x + 13 °

= 3×10 + 13 °

= 30 + 13°

= <em><u>43°</u></em>

<em><u><TBC</u></em> = 5x - 7°

= 5 × 10 - 7°

= 50 - 7°

= <em><u>43°</u></em>

<em><u>Hence</u></em><em><u>,</u></em>

<em><u>Value</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u><</u></em><em><u>ABT</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>43</u></em><em><u>°</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>value</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u><</u></em><em><u>TBC</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>43</u></em><em><u>°</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em>

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