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Kryger [21]
3 years ago
12

The ages of the people who attend a weekly yoga class at the local yoga studio are shown in the table below. 43 52 35 27 26 51 4

8 36 42 37 62 44 50 26 40 30 Which data display(s) can be used to find the median for the ages of the yoga students? I. box plot II. dot plot III. histogram
Mathematics
2 answers:
TiliK225 [7]3 years ago
7 0

Answer:

I) box plot

Step-by-step explanation:

A box plot is formed by using the five-number summary.  This summary includes:

Minimum; maximum; Q1 (first quartile); Q2 (median); Q3 (third quartile).

The median of the data will be the vertical line inside the box.  Since it specifically shows the median, a box plot is the best choice.

Mariana [72]3 years ago
3 0
A box plot b/c a box plot specifically has a point for a median. A histogram just shows the amounts and a dot plot is like a histogram but with dots.
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Devon is trying to find the unit price on a 6-pack of drinks on sale for $2.99. His sister says that at that price, each drink w
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Answer:

Step-by-step explanation:

Devon's sister is incorrect.

Note 6 drinks thats cost $2.99

2.99 divided by 6 is $0.50

Thus each drink is approx. $0.50

She would find it if she divided total number of drinks by the total price

4 0
3 years ago
HELP A.S.A.P!!!! The data to represent average test scores for a class of 16 students includes an outlier value of 78. If the ou
kolezko [41]

When the outlier is removed The mean would increase.

<u>Step-by-step explanation:</u>

Outliers are the value that lies outside the set of data. i.e. the data doesn't fit in the group.

Removing outliers can affect mean more than median. Because outlier removal sometimes affect the median but in a small percentage or sometimes it will remain the same.

Let us prove, consider 16 values one with 78 and other 15 with values nearly 85, 84 that will give the mean value as 84.

78, 84, 82, 86, 84, 85, 83, 86, 82, 85, 84, 83, 86, 85, 86, 85.

Mean =\frac{Sum of the values}{Number of values}.

Mean =\frac{78+84+82+86+84+85+83+86+82+85+84+83+86+85+86+85}{16}.

Mean =\frac{1344}{16}.

Mean = 84.

Remove 78 from the data set then the data set is 84, 82, 86, 84, 85, 83, 86, 82, 85, 84, 83, 86, 85, 86, 85 and number of data is reduced to 15.

Mean =\frac{84+82+86+84+85+83+86+82+85+84+83+86+85+86+85}{15}.

Mean =\frac{1266}{15}.

Mean = 84.4.

The mean is increased.

8 0
3 years ago
Preliminary data analyses indicate that it is reasonable to use a t-test to carry out the specified hypothesis test. Perform the
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<h2>Answer with explanation:</h2>

By considering the given information, we have

Null hypothesis : H_0: \mu=35.0

Alternative hypothesis : H_1: \mu\neq35.0

Since the alternative hypothesis is two-tailed , so the test is a two-tailed test.

Given : Sample size : n= 20, since sample size is less than 30 so the test applied is a t-test.

\overline{x}=41.0    ;    \sigma= 3.7

Test statistic : t=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}

i.e. t=\dfrac{41.0-35.0}{\dfrac{3.7}{\sqrt{20}}}=7.252112359\approx7.25

Degree of freedom : n-1 = 20-1=19

Significance level = 0.01

For two tailed,  Significance level =\dfrac{0.01}{2}=0.005

By using the t-distribution table, the critical value of t =t_{19, 0.005}=2.861

Since , the observed t-value (7.25) is greater than the critical value (2.861) .

So we reject the null hypothesis, it means we have enough evidence to support the alternative hypothesis.

We conclude that there is some significance difference between the mean score for sober women and 35.0.

3 0
3 years ago
8 plus 7 equals 6 + blank
kobusy [5.1K]
8 + 7 = 15, so 6 + 9 = 15
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3 years ago
How to breakdown fraction
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Divide it by 2, since you can make it into a half.
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3 years ago
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