C) 3
the sqrt of 12-3 is 3 and the sqrt of 36 is 6 so 3 is your answer
Answer/Step-by-step explanation:
Given, 
The table for the function are:
When x = -2





When x = -1




When x = 0




When x = 1


When x = 2



Good bless you brother I wish I can help you
Answer:
Step-by-step explanation:
using pythagoras theorem
a^2+b^2=c^2
7^2+KL^2=25^2
49+KL^2=625
KL^2=625-49
KL=
KL=24
take M as reference angle
using tan rule
tan M=/opposite/adjacent
tan M=KL/ML
tan M=24/7
3 consecutive integers : x, x + 1, x + 2
x + (x + 1) + (x + 2) = 108...ur equation
3x + 3 = 108...ur equation that has been simplified some