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2 years ago

How to find the endpoint when given the midpoint and one of the end points

1 answer:

4 0

You have to go through your x-axis and up or down you y-axis and then determine if the end point are on the right plot form

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Find a parametrization of the line in which the planes x + y + z = -6 and y + z = -8 intersect.

rewona [7]

Answer:

L(x,y) = (2,-8,0) + (0,-1,1)*t

Step-by-step explanation:

for the planes

x + y + z = -6 and y + z = -8

the intersection can be found subtracting the equation of the planes

x + y + z - ( y + z ) = -6 - (-8)

x= 2

therefore

x=2

z=z

y= -8 - z

using z as parameter t and the point (2,-8,0) as reference point , then

x= 2

y= -8 - t

z= 0 + t

another way of writing it is

L(x,y) = (2,-8,0) + (0,-1,1)*t

6 0

3 years ago

Which is a true statement?

myrzilka [38]

B is correct because -6.75 is smaller than -6.5

8 0

3 years ago

Read 2 more answers

Two different families pay for entry into a water park.

icang [17]

Answer:

Adult ticket: $7

Child ticket: $2

Step-by-step explanation:

Set up a system of equations where a represents the cost of one adult ticket and c is the cost of one child ticket:

2a + 3c = 20

a + 4c = 15

Solve by elimination by multiplying the bottom equation by -2:

2a + 3c = 20

-2a -8c = -30

Add them together:

-5c = -10

c = 2

Now, we can plug in 2 as c to find the value of a:

2a + 3c = 20

2a + 3(2) = 20

2a + 6 = 20

2a = 14

a = 7

6 0

3 years ago

Can anybody tell me the answers to number 1, 2 & 3 ???!!!!

Novay_Z [31]

Problem 1

Domain = {-1, -3, 2, 1}

Range = {5, 0, 2}

The domain is the set of possible inputs and the range is the set of possible outputs. This is a function because each input goes to exactly one output.

========================================

Problem 2

This is a function as well. We do not have any input going to multiple outputs.

Domain = {-2, -3, 5}

Range = {6, 7, 8}

========================================

Problem 3

This is not a function. The input -4 goes to more than one output (outputs 3 and -1 at the same time)

Domain = {-4, -2, 0}

Range = {3, -1, -2, 4}

6 0

3 years ago

How do you solve this? cosθ-tanθcosθ=0

laila [671]

First, lets note that $tan(\theta)\cdot cos(\theta)=sin(\theta)$ . This leads us with the following problem:

$cos(\theta)-sin(\theta)=0$

Lets add sin on both sides, and we get:

$cos(\theta)=sin(\theta)$

Now if we divide with sin on both sides we get:

$\frac{cos(\theta)}{sin(\theta)}=1$

Now we can remember how cot is defined, it is (cos/sin). So we have:

$cot(\theta)=1$

Now take the inverse of cot and we get:
$\theta=cot^{-1}(1)=\pi\cdot n+ \frac{\pi}{4} , \quad n\in \mathbb{Z}$

In general we have $cot^{-1}(1)=\frac{\pi}{4}$ , the reason we have to add pi times n, is because it is a function that has multiple answers, see the picture:

4 0

3 years ago