Step-by-step explanation:
The region represented by y<8 is called a semi-space or hemi-space given that the complete R3 space is split in two by an infinit plane in y=8
The result is two semi-space where axis X and Z aren't limited: One space in y<8 and other space in y>8
Answer:
-30r+15
Step-by-step explanation:
Apply the distributive law:
20(-1.5r)+20 · 0.75
Apply minus plus rules:
-20 · 1.5r +20 · 0.75
Simplify:
-20 · 1.5r + 20 · 0.75 = -30r+15
I hope it's right!! :)
For
![P(x)=3x^3-2x^2+5x-2](https://tex.z-dn.net/?f=%20P%28x%29%3D3x%5E3-2x%5E2%2B5x-2)
all possible rational zeroes are all the possible factors of the constant term -2 express over coefficient of the term with the highest degree of the polynomial which is 3
These are
![\frac{-1}{3}, \frac{1}{3},\frac{-2}{3}, \frac{2}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B-1%7D%7B3%7D%2C%20%5Cfrac%7B1%7D%7B3%7D%2C%5Cfrac%7B-2%7D%7B3%7D%2C%20%5Cfrac%7B2%7D%7B3%7D)
For
![R(x)=12x^3-17x^2-27x-30](https://tex.z-dn.net/?f=%20R%28x%29%3D12x%5E3-17x%5E2-27x-30)
all possible rational zeroes are all the possible factors of the constant term -30 express over coefficient of the term with the highest degree of the polynomial which is 12
These are
![\frac{-1}{12}, \frac{1}{12},\frac{-1}{6}, \frac{1}{6},\frac{-1}{4}, \frac{1}{4},\frac{-5}{12}, \frac{5}{12},\frac{-1}{2}, \frac{1}{2},\frac{-5}{6}, \frac{5}{6},\frac{-5}{4}, \frac{5}{4},\frac{-5}{2}, \frac{5}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B-1%7D%7B12%7D%2C%20%5Cfrac%7B1%7D%7B12%7D%2C%5Cfrac%7B-1%7D%7B6%7D%2C%20%5Cfrac%7B1%7D%7B6%7D%2C%5Cfrac%7B-1%7D%7B4%7D%2C%20%5Cfrac%7B1%7D%7B4%7D%2C%5Cfrac%7B-5%7D%7B12%7D%2C%20%5Cfrac%7B5%7D%7B12%7D%2C%5Cfrac%7B-1%7D%7B2%7D%2C%20%5Cfrac%7B1%7D%7B2%7D%2C%5Cfrac%7B-5%7D%7B6%7D%2C%20%5Cfrac%7B5%7D%7B6%7D%2C%5Cfrac%7B-5%7D%7B4%7D%2C%20%5Cfrac%7B5%7D%7B4%7D%2C%5Cfrac%7B-5%7D%7B2%7D%2C%20%5Cfrac%7B5%7D%7B2%7D)
21+-3 so 18 to 24 is the answer
Answer:
the mean is 53 the median is 54 the mode is none