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3 years ago

Explain how you know the values of the digits in the number 58

Mathematics

1 answer:

AleksAgata [21]3 years ago

6 0

The value of 5 is 50 because its in the tens place the value of 8 is 8 because its in the ones place.

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What is the value of a?

Leno4ka [110]

Answer:

A=60

Step-by-step explanation:

Add 28+20+12

A=60

5 0

2 years ago

Read 2 more answers

Find the value of the expression when x=1 and y=4. 7x+4+5=

Agata [3.3K]

Answer: umm wheres y at? after the Equal sign?

Step-by-step explanation:

6 0

3 years ago

The slope of a line is -4/5 what is the rise if the run is 20?

Strike441 [17]

Answer:

rise= -16

Step-by-step explanation:

Please see the attached picture for the full solution.

6 0

3 years ago

CAN SOMEONE PLEASE HELP ME!!!!

love history [14]

Answer:

The balance after the payment is $1263.84.

Step-by-step explanation:

The formula for amount after compound interest is

$A=P(1+\frac{r}{n})^{t}$

Where, P is principal, r is rate of interest, n is number of time interest compounded in a period, number of periods.

According to the given information,

P=1455.69

r=0.128

n=365

t=45

Put these values in the above formula,

$A=1455.69(1+\frac{0.128}{365})^{45}$

$A\approx 1478.84$

The amount after compound interest is $1478.84. Add late fee chages $35 in this amount and subtract the payment of $250. So, the balance amount after payment is

$Balance=1478.84+35-250=1263.84$

Therefore the balance after the payment is $1263.84.

8 0

3 years ago

A particle moves on the hyperbola xy=18 for time t≥0 seconds. At a certain instant, y=6 and dydt=8. What is x that this instant?

professor190 [17]

Answer:

The value of x at this instant is 3.

Step-by-step explanation:

Let $x\cdot y = 18$ , we get an additional equation by implicit differentiation:

$x\cdot \frac{dy}{dt}+y\cdot \frac{dx}{dt} = 0$ (1)

From the first equation we find that:

$x = \frac{18}{y}$ (2)

By applying (2) in (1), we get the resulting expression:

$\frac{18}{y}\cdot \frac{dy}{dt}+y\cdot \frac{dx}{dt} = 0$ (3)

$y\cdot \frac{dx}{dt}=-\frac{18}{y}\cdot \frac{dy}{dt}$

$\frac{dx}{dt} = -\frac{18}{y^{2}} \cdot \frac{dy}{dt}$

If we know that $y = 6$ and $\frac{dy}{dt} = 8$ , then the first derivative of x in time is:

$\frac{dx}{dt} = -\frac{18}{6^{2}} \cdot (8)$

$\frac{dx}{dt} = -4$

From (1) we determine the value of x at this instant:

$x\cdot \frac{dy}{dt} = -y\cdot \frac{dx}{dt}$

$x = -y\cdot \left(\frac{\frac{dx}{dt} }{\frac{dy}{dt} } \right)$

$x = -6\cdot \left(\frac{-4}{8} \right)$

$x = 3$

The value of x at this instant is 3.

4 0

2 years ago