Answer:
-6i
Step-by-step explanation:
Complex roots always come in pairs, and those pairs are made up of a positive and a negative version. If 6i is a root, then its negative value, -6i, is also a root.
If you want to know the reasoning, it's along these lines: to even get a complex/imaginary root, we take the square root of a negative value. When you take the square root of any value, your answer is always "plus or minus" whatever the value is. The same thing holds for complex roots. In this case, the polynomial function likely factored to f(x) = (x+8)(x-1)(x^2+36). To solve that equation, you set every factor equal to zero and solve for the x's.
x + 8 = 0
x = -8
x - 1 = 0
x = 1
x^2 + 36 = 0
x^2 = -36 ... take the square root of both sides to get x alone
x = √-36 ... square root of an imaginary number produces the usual square root and an "i"
x = ±6i
You can multiply 0.129 and 0.3 by 10 each to make it a little easier to see what to do.
0.129 / 0.3 = 1.29 / 3
Simple long division will take you to 0.43
The piecewise function all the way to the left (x + 3) should have an ending point shaded in. [At x = -2] The next function ((x^2) -1) should have both ending points left unshaded. Finally, the logarithm function should have a shaded in starting point [At x = 1] and should have an unshaded ending point at x = 3.
Answer:
The axis of symmetry should be x = 2.
Step-by-step explanation:
:)
