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suter [353]
3 years ago
6

Find the solution set of the inequality: 8x+2 > 348x+2>34

Mathematics
2 answers:
Sphinxa [80]3 years ago
5 0

Answer: I guess is no solution

Step-by-step explanation:

Vsevolod [243]3 years ago
4 0

Answer:

21

Step-by-step explanation:

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Please I need some answers
Ilia_Sergeevich [38]
-6 x -4 = 24
24/-6 = -4
24/-4 = -6

Hope this helps :)
7 0
3 years ago
Find the exact value of cos(a+b) if cos a=-1/3 and cos b=-1/4 if the terminal side if a lies in quadrant 3 and the terminal side
maria [59]

Answer:

cos(a + b) = \frac{1}{12}(1-2\sqrt{30})

Step-by-step explanation:

cos(a + b) = cos(a).cos(b) - sin(a).sin(b) [Identity]

cos(a) = -\frac{1}{3}

cos(b) = -\frac{1}{4}

Since, terminal side of angle 'a' lies in quadrant 3, sine of angle 'a' will be negative.

sin(a) = -\sqrt{1-(-\frac{1}{3})^2} [Since, sin(a) = \sqrt{(1-\text{cos}^2a)}]

         = -\sqrt{\frac{8}{9}}

         = -\frac{2\sqrt{2}}{3}

Similarly, terminal side of angle 'b' lies in quadrant 2, sine of angle 'b' will be  negative.

sin(b) = -\sqrt{1-(-\frac{1}{4})^2}

         = -\sqrt{\frac{15}{16}}

         = -\frac{\sqrt{15}}{4}

By substituting these values in the identity,

cos(a + b) = (-\frac{1}{3})(-\frac{1}{4})-(-\frac{2\sqrt{2}}{3})(-\frac{\sqrt{15}}{4})

                = \frac{1}{12}-\frac{\sqrt{120}}{12}

                = \frac{1}{12}(1-\sqrt{120})

                = \frac{1}{12}(1-2\sqrt{30})

Therefore, cos(a + b) = \frac{1}{12}(1-2\sqrt{30})

5 0
3 years ago
What is the line segments between (4,-6) and (-6,-16)?
sergejj [24]
The line segments between (4,-6) and (-6,-16) is 1.

slope = y2 -y1 /x2-x1 = -16+6/-6-4=-10/-10=1
6 0
3 years ago
Fill in the blank (no word bank)
anastassius [24]

Answer:

1.Angle B

2.Angle C

If It Is Wronge Sory

8 0
3 years ago
Can you please help?
tigry1 [53]

Step-by-step explanation:

f/p = p(1+i)^n

p= 2500

i=0.03 =3%

n=4

2500(1 + 0.03)^4

5 0
3 years ago
Read 2 more answers
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