Answer:
Given that rotating 90 degrees clockwise around the origin switches the x andy values and makes the new y value negative, we can, for example, switch (2, 1) to (1, -2). 180 degrees clockwise simply makes both values negative (-2, -1), and 270 degrees clockwise switches them and makes the new y value negative (-1, 2), we can plug those in to our JM endpoints to turn (-5, 1) into (-1, -5) and (-6, 2) into (-2, -6)
Step-by-step explanation:
Answer:
A.1 Exercise
2. Reduce the intake of salt
3. Reduce intake of fatty foods
4. Eating well balance diet
B.1. Regular exercise
2. Avoid smoking
3. Avoid excessive intake of alcohol
4. Reduce intake of cholesterol
Answer:
4 ounces of corn and 4 ounces of squash
Step-by-step explanation:
Let S be the no. of ounces of squash
Let C be the no. of ounces of corn
C》2 --> (A)
S》C --> (B)
Total protein 》 3
½C + ¼S》3 --> (C)
Solve A and C simultaneously
½(2) + ¼S = 3
¼S = 2
S = 8
C = 2, S = 8
Solve B and C simultaneously
½S + ¼S = 3
¾S = 3
S = 4
C = 4, S = 4
Three possible extreme combinations
C = 2, S = 8: Total = 10
C = 4, S = 4: Total = 8
Minimum is 8 ounces
Answer:
x ≈ 63.27
Step-by-step explanation:
Using the tangent ratio in the right triangle
tan49° =
=
=
( multiply both sides by 55 )
55 × tan49° = x , then
x ≈ 63.27 ( to the nearest hundredth )
Answer:
C. The distribution for town A is symmetric, but the distribution for
town B is negatively skewed.
Step-by-step Explanation:
From the box plots attached in the diagram below, which shows data of low temperatures for town A and town B for some days, we can compare the shapes of the box plot by visually analysing both box plots and how the data for each town is distributed.
=> For town A, the shape of the box plot is symmetric because both quartiles seem equal, and the median also divides the rectangular box into two equal halves. Both whiskers also appear to be of equal lengths.
The box plot for Town A takes a symmetric shape, and this shows a typical normal distribution of data.
=> On the other hand, Town B data distribution is different. The median seem close to the top half of the box and does not divide the box into equal halves. This shows the distribution is skewed. Since the whisker is shorter from the upper end of the box to the left side, we can infer that the distribution for Town B is skewed to the left, and it is negatively skewed.
=> The right comparison of the shapes of the box plots is "C. The distribution for town A is symmetric, but the distribution for town B is negatively skewed."