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Serggg [28]
2 years ago
9

Please help me answer this question genius

Mathematics
1 answer:
kolbaska11 [484]2 years ago
7 0

Answer:

  x ∈ {-0.465, 1.014}

Step-by-step explanation:

The equation can be cast in the form f(x) = 0, and solved easily using a graphing calculator. That shows x ≈ -0.465 and x ≈ 1.014. The same calculator can iterate the roots to full calculator precision.

__

The equation can be made a quadratic by the substitution ...

  z = e^(2x)

Then we have ...

  2\cosh(2x)-\sinh(2x)=4\\\\2\cdot\dfrac{e^{2x}+e^{-2x}}{2}-\dfrac{e^{2x}-e^{-2x}}{2}-4=0\qquad\text{use exponential identities}\\\\2z+2z^{-1}-z+z^{-1}-8=0\qquad\text{multiply by 2, substitute z}\\\\z^2 -8z+3=0\qquad\text{multiply by z}\\\\z=\dfrac{8\pm\sqrt{(-8)^2-4(1)(3)}}{2(1)}=4\pm\sqrt{13}\\\\x=\dfrac{\ln(z)}{2}=\dfrac{\ln(4\pm\sqrt{13})}{2}\approx\{-0465133,1.014439\}

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Answer:

C

Step-by-step explanation:

It is not possible to put all 10 things on a 4 sided cube, and yes a standard number cube is four sided.

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3 years ago
the piece wise defined function f(x) is graphed below. What is the value of f(2)? PLS HELP THIS IS TIMED
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We have to look at the full dot

5 0
3 years ago
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erastovalidia [21]

Step-by-step explanation:

so...the answer is C.27.7m

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Read 2 more answers
Can someone help please?
Aliun [14]

Answer:

L=7.295

Step-by-step explanation:

I can't type in a square root symbol so here's the sequence:

divide both sides by 2 Pi

square both sides

now you have:

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multiply both sides by 32

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3 years ago
Determine the values of the parameter s for which the system has a unique​ solution, and describe the solution. sx 1 minus 2 sx
JulijaS [17]

Note: The equations written in this questions are not appropriately expressed, however, i will work with hypothetical equations that will enable you to solve any problems of this kind.

Answer:

For the system of equations to be unique, s can take all values except 2 and -2

Step-by-step explanation:

2sx_{1} + 4x_{2} = -3\\2x_{1} + sx_{2} = 4

\left[\begin{array}{ccc}2s&4\\2&s\end{array}\right] \left[\begin{array}{ccc}x_{1} \\x_{2} \end{array}\right] = \left[\begin{array}{ccc}-3 \\6 \end{array}\right]

For the system to have a unique solution, \begin{vmatrix} 2s & 4 \\ 2 & s \end{vmatrix} \neq 0

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6 0
4 years ago
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