10. Write a number sentence for the model. Let one white tile equal +1 and one black tile equal –1.

Mathematics

1 answer:

Darina [25.2K]4 years ago

5 0

The Correct answer to it is -14 - (-6) = - 8

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Solve by substitution (show steps) -3x-4y=10 -6x+y=-16

natali 33 [55]

1) -3x-4y=10 ==> - 3x = 10+4y ===> 3x= -10-4y==> x=(-10-4y)/3
Now replace x by its value in 2)

2) -6x+y=-16 ==> - 6[( - 10- 4y)/3] + y = -16 ==> -2[(-10-4y] +y =- 16
+20+8y+y =- 16==> 9y = - 16 - 20 ==> 9y = -36 & y = - 4.

Now replace y by (- 4) in any of the 2 equations & you will find x = 2

6 0

4 years ago

Can someone please help!

Setler [38]

Answer:

- 3+2x/x-3

Step-by-step explanation:

8 0

3 years ago

1. Find the vertices and locate the foci for the hyperbola whose equation is given.

Irina18 [472]

$\bf \cfrac{(x-{{ h}})^2}{{{ a}}^2}-\cfrac{(y-{{ k}})^2}{{{ b}}^2}=1
\qquad center\ ({{ h}},{{ k}})\qquad
 vertices\ ({{ h}}\pm a, {{ k}})\\\\
-----------------------------\\\\
\textit{now let's take a look at yours}
\\\\\\
49x2 - 16y2 = 784\implies \cfrac{49x^2}{784}-\cfrac{16y^2}{784}=1
\\\\\\
\cfrac{x^2}{16}-\cfrac{y^2}{49}=1\implies \cfrac{(x-0)^2}{4^2}-\cfrac{(y-0)^2}{7^2}=1
\\\\\\
recall\implies center\ ({{ h}},{{ k}})\qquad vertices\ ({{ h}}\pm a, {{ k}})
\\\\\\
$

$\bf \textit{now, for the foci, the foci are "c" distance from the center point}\\\\\
whereas\qquad c=\sqrt{a^2+b^2}\qquad \textit{ that is }\qquad h\pm \sqrt{a^2+b^2}$

notice your "a" and "b" components, to get the distance "c" from the center to either foci and the vertices, of course, are h + a, k and h - a, k

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3 years ago

Mary says the pen for her horse is an acute right triangle. Is this possible? EXPLAIN!!!

exis [7]

we know that

An acute triangle is a triangle with all three angles acute (less than $90\°$ ).