The general way to work this out is to solve the general expression for
the remaining quantity versus half-life, using logarithms. But that's not
necessary with these numbers.
Look at the numbers:
-- 3 mg is 1/4 of 12 mg.
-- 1/4 is the product of (1/2) x (1/2).
-- So the 3 mg is what's left of 12 mg after 2 half-lives.
The 26 minutes must be two half-lives.
-- The half-life of that substance is 26/2 = <em>13 minutes</em>.
Go Maggie !
Answer:
<h3>7:1</h3>
Step-by-step explanation:
Let the weight of mr nazeer be x
Let the weight of his son be y
If the weight of mr nazeer is 7 times that of his son, then x = 7y
To get the ratio of their weight:
Ratio = weight of father/weight of son
Ratio = 7y/y
Ratio = 7/1
Ratio = 7:1
Hence the ratio of their weights is 7:1
Answer:
34
Step-by-step explanation:
F(x) = 2x^3 - 7x + 1
Let x= 3
F(3) = 2* 3^3 - 7*3 + 1
= 2 * 27 -21+1
= 54 -21 + 1
= 34
Only the upper-left statement is NOT true.
