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xeze [42]
3 years ago
8

Suppose the cost of publishing x books is C(x) = 10000 + 25

tle="\sqrt{x}" alt="\sqrt{x}" align="absmiddle" class="latex-formula">, find the marginal cost at x=100 by using the derivative. Compare this with the difference C(101) - C(100).
Mathematics
1 answer:
dusya [7]3 years ago
6 0

Answer:

\frac{dC}{dQ} \approx 1.25, C(101)-C(100) = 1.247, \delta = 0.24\,\%

Step-by-step explanation:

The marginal cost function is:

\frac{dC}{dQ} = 12.5\cdot x^{-\frac{1}{2} }

The marginal cost for 100 books is:

\frac{dC}{dQ} \approx 1.25

The difference is:

C(101)-C(100) = 25\cdot (101^{\frac{1}{2} }-100^{\frac{1}{2} })

C(101)-C(100) = 1.247

The relative error is:

\delta = \frac{|1.25-1.247|}{1.25}\times 100\,\%

\delta = 0.24\,\%

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