You swap x and y. for example, the first set is (0,1) so the inverse would be (1,0)
Answer:
Vertical angle=9.5°
Time to reach maximum height = 1.24seconds
Step-by-step explanation:
The maximum distance x is reached when rope swings to a maximum height, maximum height is gotten from the equation KE= 1/2MU^2 = MgH = MgL= Mgl(1- cos theta.
Where theta is the vertical angle, U=2m/s and L= 15m
2gl -2glcostheta=U^2
2gl U^2=2gl cos theta
But theta= Acos(1- U^2)/2gl
Acos(1-/(2×9.8×15)
Theta =9.5°
Maximum height li given by
Lsintheta
But X= UxT
T=X/UX= Lsintheta/U = 15sin9.5 /2 =1.24seconds
<u>Given</u>–
AB = 12 Cm
CD = 14 Cm
PO = 10 Cm
AP = 1/2 × 12 = 6 Cm
<u>Construction</u>–
Draw NO such that it is the perpendicular bisector of CB.
Hence,
ND = 1/2 × 14 = 7 Cm
To Find,
Measure of NO
<u>Solution</u>,
Here, PO Perpendicular to AB
Hence, APO is a right-angled triangle–
AO² = PO² + AP²
Or, AO² = 10 ² + 6 ²
Or, AO² = 36 + 100
Or, AO = √136 Cm
Or, AO = 11.66 Cm
Also, AO = OD = 11.66 Cm
( Radius of the same circle )
Now, in triangle OND,
OD² = ON² + ND ²
Or, 11.66 ² = ON² + 7²
Or, 136 = ON² + 49
Or, ON ² = 136 – 49
Or, ON ² = 87
Or, ON ² = √87
Or, ON = 9.3 Cm
Therefore, the appropriate length from center to CD is 9.3 Cm.
Answer:
C.) The amount of money she saved before attending lessons.