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3 years ago

Which of these are the intercepts of the graph of y = 3x – 12?

2 answers:

7 0

Hello there! :) To find one intercept, you'll need to set the other one to 0. For instance: x intercept: y=0 y intercept: x=0 X Intercept: 0= 3x-12 Add 12 to both sides to isolate x. 0+12= 3x-12+12 12= 3x Divide both sides by 3. 12/3=3x/3 4= x intercept Y Intercept: You could plug in x as 0 and solve, but a quick way to find it in a slope-intercept equation is to look at the number at the end (without the x.) In this problem it would be -12. Hope this helps! :) Let me know if you need any additional helps.

charle [14.2K]3 years ago

5 0

Y intercept is (0,-12), the x-intercept is (4,0)

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Find the invers of the relation (0, 1), (1,-2), (2, 4), (3, -1), (4, 0)

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3 years ago

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You and your friends find a rope that hangs down 15 m from a high tree branch right at the edge of a river. You find that you ca

Crazy boy [7]

Answer:

Vertical angle=9.5°

Time to reach maximum height = 1.24seconds

Step-by-step explanation:

The maximum distance x is reached when rope swings to a maximum height, maximum height is gotten from the equation KE= 1/2MU^2 = MgH = MgL= Mgl(1- cos theta.

Where theta is the vertical angle, U=2m/s and L= 15m

2gl -2glcostheta=U^2

2gl U^2=2gl cos theta

But theta= Acos(1- U^2)/2gl

Acos(1-/(2×9.8×15)

Theta =9.5°

Maximum height li given by

Lsintheta

But X= UxT

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2 years ago

What numbers add up to 31

kkurt [141]

15 plus 16 equals 31

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3 years ago

If the length of AB is 10 cm from the center and has a length of 12, find the approximate length from the center to CD.

Lynna [10]

Given–

AB = 12 Cm

CD = 14 Cm

PO = 10 Cm

AP = 1/2 × 12 = 6 Cm

Construction–

Draw NO such that it is the perpendicular bisector of CB.

Hence,

ND = 1/2 × 14 = 7 Cm

To Find,

Measure of NO

Solution,

Here, PO Perpendicular to AB

Hence, APO is a right-angled triangle–

AO² = PO² + AP²

Or, AO² = 10 ² + 6 ²

Or, AO² = 36 + 100

Or, AO = √136 Cm

Or, AO = 11.66 Cm

Also, AO = OD = 11.66 Cm

( Radius of the same circle )

Now, in triangle OND,

OD² = ON² + ND ²

Or, 11.66 ² = ON² + 7²

Or, 136 = ON² + 49

Or, ON ² = 136 – 49

Or, ON ² = 87

Or, ON ² = √87

Or, ON = 9.3 Cm

Therefore, the appropriate length from center to CD is 9.3 Cm.

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