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Vilka [71]
3 years ago
5

;11x+7" alt="f(x) = −3x2−11x+7" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
bixtya [17]3 years ago
4 0

Answer:

x=   \frac{ - 11 +  \sqrt{205} }{6}  \:  \:  \:  \:  \: or \:  \:  \:  \:  \\x  =  \frac{ - 11 -  \sqrt{205} }{6}

Step-by-step explanation:

- 3x {}^{2}  - 11x + 7 = 0 \\ 3x {}^{2}  + 11x - 7 = 0

here,

a = 3 \\ b = 11 \\ c =  - 7

now,

D = b {}^{2}  - 4ac \\  = (11) {}^{2}  - 4(3)( - 7) \\  = 121 + 84 \\  = 205  > 0 \\

so,

x =  \frac{ - b +  -  \sqrt{b {}^{2}  - 4ac} }{2a}  \\  \\  =   \frac{ - 11 +  -  \sqrt{205} }{2(3)}  \\  =   \frac{ - 11 +  -   \sqrt{205}  }{6}  \\  \\  =   \frac{ - 11 +  \sqrt{205} }{6}  \:  \:  \:  \:  \: or \:  \:  \:  \:  =  \frac{ - 11 -  \sqrt{205} }{6}

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madam [21]

Given:

The parent function is

f(x)=x^2

Consider the transformed function is g(x) instead of f(x) because both functions are different.

g(x)=-5(x-4)^2-8

Step-by-step explanation:

We have,

f(x)=x^2

g(x)=-5(x-4)^2-8

It can be written as

g(x)=-5f(x-4)-8            ...(i)

The translation is defined as

g(x)=kf(x+a)+b                .... (ii)

Where, k is stretch factor, a is horizontal shift and b is vertical shift.

If 0<|k|<1, then the graph compressed vertically by factor k and if |k|>1, then the graph stretch vertically by factor k.

If k is negative, then f(x) is reflected across the x-axis to get g(x).

If a>0, then the graph shifts a units left and if a<0, then the graph shifts a units right.

If b>0, then the graph shifts b units up and if b<0, then the graph shifts b units down.

On comparing (i) and (ii), we get

a=-4, f(x) shifts 4 units right.

b=-8, f(x) shifts 8 units down.

k=-5, it is negative so f(x) reflected across the x-axis.

|k|=|-5|=5>1, so f(x) stretched vertically by factor 5.

Therefore, the function f(x) reflected across the x-axis, stretched vertically by factor 5 and shifted 4 units right 8 units down to get g(x).

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Answer:

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Step-by-step explanation:

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Required

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Step-by-step explanation:

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The end points of line segment PQ are P(1, 3), and Q(7, 7). What is the midpoint of line segement PQ?
dangina [55]

Answer:

D) (4, 5)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

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  2. Parenthesis
  3. Exponents
  4. Multiplication
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  6. Addition
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Step-by-step explanation:

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Q(7, 7) → x₂ = 7, y₂ = 7

<u />

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Simply plug in your coordinates into the midpoint formula to find midpoint

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  2. [Midpoint] Add:                                                                                               \displaystyle (\frac{8}{2},\frac{10}{2})
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