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Vilka [71]
3 years ago
5

;11x+7" alt="f(x) = −3x2−11x+7" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
bixtya [17]3 years ago
4 0

Answer:

x=   \frac{ - 11 +  \sqrt{205} }{6}  \:  \:  \:  \:  \: or \:  \:  \:  \:  \\x  =  \frac{ - 11 -  \sqrt{205} }{6}

Step-by-step explanation:

- 3x {}^{2}  - 11x + 7 = 0 \\ 3x {}^{2}  + 11x - 7 = 0

here,

a = 3 \\ b = 11 \\ c =  - 7

now,

D = b {}^{2}  - 4ac \\  = (11) {}^{2}  - 4(3)( - 7) \\  = 121 + 84 \\  = 205  > 0 \\

so,

x =  \frac{ - b +  -  \sqrt{b {}^{2}  - 4ac} }{2a}  \\  \\  =   \frac{ - 11 +  -  \sqrt{205} }{2(3)}  \\  =   \frac{ - 11 +  -   \sqrt{205}  }{6}  \\  \\  =   \frac{ - 11 +  \sqrt{205} }{6}  \:  \:  \:  \:  \: or \:  \:  \:  \:  =  \frac{ - 11 -  \sqrt{205} }{6}

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jarptica [38.1K]

Answer: 3 zeroes.


Explanation:-

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8 0
4 years ago
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Lisa [10]

w represents width

4w represents length

d represents diagonal

w2 + (4w)2 = d2

w2 + 16w2 = d2

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±w√17 = d

 

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3 years ago
The sum of three consecutive integers is greater than 66. What is the smallest possible product of the largest and smallest of t
AysviL [449]

Answer:

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Step-by-step explanation:

So naturally at first sight for this question we would think -->

Oh 3 consecutive integers = 66 --> 66/3 = 22 (n-1), (n+1) so --> 21, 22, and 23.

But no. At second look it is the sum of 3 consecutive integers is greater than 66. So we find the next possible pair since it says smallest possible product.

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