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Elodia [21]
3 years ago
10

12 times a number decreased by 5 is no more than 55

Mathematics
2 answers:
bagirrra123 [75]3 years ago
7 0

Answer:

Well, try 1 for starters.

But I think you need an inequality written. Is that what you are asking?

Step-by-step explanation:

lions [1.4K]3 years ago
6 0

Answer:

  12n -5 ≤ 55

Step-by-step explanation:

12 times a number (represented by n) is 12n.

"Decreased by 5" means 5 is subtracted from the product, giving 12n-5.

"Is no more than 55" means "is less than or equal to 55".

Then the expression written using math symbols is ...

  12n -5 ≤ 55

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Simplify the following expression.
Rzqust [24]

Step-by-step explanation:      

<u>Step 1: Add the numbers: 9.5 +6.2 = 15.7</u>

=8.6\left(15.7-3.5^2\right)

3.5^2=12.25

=8.6\left(15.7-12.25\right)

<u>Step 2: Subtract the numbers: 15.7 - 12.25 = 3.45</u>

= 3.45X 8.6

<u>Step 3: Multiply the numbers: 8.6 × 3.45 = 29.67</u>

<u />=29.67<u />

<u />

- To solve this equation, the first step is to add the numbers 9.5 + 6.2 into the equation and it will lead to 15.7 as the number for step one.

- To solve this equation, the second step is to subtract the numbers 15.7 - 12.25 into the equation and it will lead to 3.45 as the answer.

- To solve this equation, the third step is to multiply the numbers 8.6 x 3.45 into the equation and it will lead 29.67 as the final answer for the whole equation.

Answer:      

=29.67

 

Hope this helps.

3 0
2 years ago
Write a number of grams between 10 and 20, and then write an equivalent amount in milligrams.
oksano4ka [1.4K]

Answer:

15 grams and 15000 milligrams

Step-by-step explanation:

3 0
2 years ago
I need help with this please!!!
Andru [333]

Answer:

U = \frac{TE}{3}

Step-by-step explanation:

Given

T = \frac{3U}{E}

Multiply both sides by E to clear the fraction

TE = 3U ( divide both sides by 3 )

\frac{TE}{3} = U

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NEED HELP FAST WILL MARK BRAINLIEST
Tju [1.3M]
Pretty sure the answer is 18

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The expression 3(x-9) is equivalent to
Inessa05 [86]
The answer to this question would be D. 3(x)-3(9)
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