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3 years ago

14

When olivia started a business the amount of profit she had was -$1550 during the first six months, her profit increase by $250

each month what was the amount of olivia's profit at the end of the first six months?

1 answer:

Llana [10]3 years ago

4 0

She is still in debt by $50 by the end of six months. -1550+250=-1300+250=-1050+250=-800+250=-550+250=-300+250=-50

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What’s the volume of the rectangular prism in cubic meters

GarryVolchara [31]

Answer:

Volume of the prism=60m3

Step-by-step explanation:

Volume of any prism=height*width*length

Volume of the prism=3m*5m*4m=60m3

Volume of the prism=60m3

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2 years ago

The breaking strength of a cable is assumed to be lognormally distributed with a mean of 75 and standard deviation of 20. • If t

son4ous [18]

Answer:

If the load of magnitude 50 is hung from the cable, determine the probability of failure of the cable?

There is a 10.56% probability of failure of the cable.

If the load can take values 30, 50, and 70 with probabilities 0.2, 0.35, and 0.45 respectively, determine the probability of failure of the cable?

There is a 15.87% probability of failure of the cable.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

The breaking strength of a cable is assumed to be lognormally distributed with a mean of 75 and standard deviation of 20. This means that $\mu = 75, \sigma = 20$ .

If the load of magnitude 50 is hung from the cable, determine the probability of failure of the cable?

This is the pvalue of Z when $X = 50$ .

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{50 - 75}{20}$

$Z = -1.25$

$Z = -1.25$ has a pvalue of 0.1056.

There is a 10.56% probability of failure of the cable.

If the load can take values 30, 50, and 70 with probabilities 0.2, 0.35, and 0.45 respectively, determine the probability of failure of the cable?

Now we have that

$X = 0.2(30) + 0.35(50) + 0.45(70) = 55$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{55 - 75}{20}$

$Z = -1$

$Z = -1$ has a pvalue of 0.1587.

There is a 15.87% probability of failure of the cable.

3 0

3 years ago

F(n)=5.(-2)n-1<br>Complete the recursive formula of f(n).

Alex73 [517]

Answer:

a(n) = $(-2)(a_{n-1})$

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Step-by-step explanation:

The given expression is in the form of the explicit formula of a geometric sequence.

f(n) = $a(r)^{n-1}$

Where 'a' = First term of the sequence

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Recursive formula of a geometric sequence is,

a(n) = $(a_{n-1}).(r)^{n-1}$

a(n) = $(-2)(a_{n-1})$

Where, $a_{1}=5$

So the recursive formula will be a(n) = $(-2)(a_{n-1})$

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3 years ago

Determine the measure of ∠Y. images attached

Gwar [14]

Answer:

<h3>The answer is option C</h3>

Step-by-step explanation:

Since it's a right angled triangle we can use trigonometric ratios to find the value of ∠Y

To find the value of ∠Y we use tan

We have

$\tan(∠Y) = \frac{25}{20} \\ \tan(∠Y) = \frac{5}{4} \\ ∠Y = { \tan^{ - 1} } \frac{5}{4} \\ ∠Y = 51.34019...$

We have the final answer as

<h3>51.34°</h3>

Hope this helps you

5 0

2 years ago

Read 2 more answers

A submarine dives at a constant speed of 10 m/s at a diving angle measured from the vertical

valina [46]

Answer:

155.3 m

Step-by-step explanation:

<u>We have:</u>

θ: is the angle measured from the vertical = 75 °

v = is the speed of the submarine = 10 m/s

t = 1 min

The deep of the front end of the submarine at the end of a 1-minute drive is given by the following ratio:

$cos (\theta) = \frac{x}{d}$

<u>Where:</u>

d: is the distance traveled by the submarine in 1 minute

x: is the deep to find

The distance, d, is:

$d = v*t = 10 \frac{m}{s}* 1 min * \frac{60 s}{1 min} = 600 m$

Now, the deep is:

$cos (75) = \frac{x}{600}$

$x = cos(75)*600 = 155.3 m$

Therefore, the deep of the front end of the submarine at the end of a 1-minute drive is 155.3 m.

I hope it helps you!

3 0

3 years ago