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2 years ago

What is the sum of the first nine terms of this Sequence if the first term is 0?

Mathematics

2 answers:

Harlamova29_29 [7]2 years ago

8 0

Answer:

D. 160

Step-by-step explanation:

The sum of the sequence 1, 2, 3, 4, ... , n is n(n + 1)/2.

Here, you have the sum of 4(1, 2, 3, 4, ... , n), so the sum is 4[n(n + 1)/2]

In this case, the first term is 0, so the last term is the 8th term of the sequence above, so n = 8

4[n(n + 1)/2)] =

= 4[8(9)/2]

= 4[72/2]

= 4(36)

= 144

The closest answer is D. 160

pishuonlain [190]2 years ago

7 0

Answer:

The answer is B.

Step-by-step explanation:

First you write out the first nine multiples of 4. Then you add them.

4 + 8 + 12 + 16 + 20 + 24 + 28 + 32 + 36 = 180

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The following frequency table summarizes last week's bed sales at Cloud Nine Furniture.

Masteriza [31]

Answer:

Option A. 0.20

Step-by-step explanation:

Observations from the given frequency table are :

Total number of beds sold at Cloud Nine Furniture = 3 + 6 + 4 + 2

= 15

Number of twin beds sold = 3

Then, probability that the next bed sold will be a twin bed,

$P=\frac{\text{favorable outcome}}{\text{total number of possible outcomes}}$

$=\frac{3}{15}$

= 0.20

Therefore, the probability that the next bed sold is a twin bed will be 0.20 or 20%.

Option A. is the correct answer.

5 0

3 years ago

Read 2 more answers

Please show your work.

Nastasia [14]

Answer:

1. 8.19, 2. 25.96, 3. 3.95

Step-by-step explanation:

use soh cah toa

1. cos is adjacent/hypotenuse

cos73=x/28

multiply both sides by 28

28cos73=x=8.186

2. sin is opposite over hypotenuse

sin68=x/28

multiply both sides by 28

28sin68=x=25.961

3. sin is opposite over hypotenuse

sin26=x/9

myltiply both sides by 9

9sin26=x=3.945

8 0

2 years ago

18. During a clothing store's Bargain Days, the regular price for T-shirts is discounted to $8.25.

8090 [49]

Answer:

3.25

Step-by-step explanation:

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2 years ago

Read 2 more answers

Match each expression to its equivalent standard form.

Aleksandr [31]

Let's expand the products they are all in the form

$(a+b)(a-b)=a^2-b^2$

For the first one we have a=x and b=2i:

$(x+2i)(x-2i)=x^2-(2i)^2=x^2+4$

For the second one we have a=x-2 and b=2i:

$(x-2+2i)(x-2-2i)=(x-2)^2-(2i)^2 = x^2-4x+4+4=x^2-4x+8$

For the third one we have a=x+1 and b=i:

$(x+1+i)(x+1-i)=(x+1)^2-i^2=x^2+2x+1+1=x^2+2x+2$

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3 years ago

Approximately students attend Jones Middle School. Below is the data collected from two random samples of students regarding sch

erastova [34]

Answer:

there is nothing to select. u need to provide more info

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2 years ago