Answer:
D. 160
Step-by-step explanation:
The sum of the sequence 1, 2, 3, 4, ... , n is n(n + 1)/2.
Here, you have the sum of 4(1, 2, 3, 4, ... , n), so the sum is 4[n(n + 1)/2]
In this case, the first term is 0, so the last term is the 8th term of the sequence above, so n = 8
4[n(n + 1)/2)] =
= 4[8(9)/2]
= 4[72/2]
= 4(36)
= 144
The closest answer is D. 160
