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Ostrovityanka [42]
3 years ago
15

Solve: 3x - 2x + 4 = 5x - 4x - 8 A) 3 B) 6 C) -3 Eliminate D) no solution

Mathematics
1 answer:
SSSSS [86.1K]3 years ago
5 0
There is no solution
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For the students in your school, the mean score on a state-wide standardized test was 116. Is the mean score a parameter or a st
erastovalidia [21]
Statistic because it’s a fact and data that is being study as you go to school by the large quality of numerical data
3 0
3 years ago
Chords AB and CD intersect at point E, AE = 10, EB = 4, and CE = 8. Therefore, ED =
Genrish500 [490]
So here is how we are going to find out what is ED. 
Based on the given figure, it states that, AE is 10, and EB is 4 and CE is 8.
So, <span>(AE/CE)=(ED/EB)
10/8 = ED/4 <<multiply both sides by the common denominator which is 8 and the result would be:
80/8 = 8ED/4
10 = 2ED <<divide both sides by 2 and we get
ED = 5.
Therefore, the measurement of ED is 5. 
Hope this answer helps. Let me know if you need more help next time!</span>
5 0
3 years ago
Read 2 more answers
Please help with my question it is the millers shower uses 25 gallons of water for a 10 min shower. Now how many gallons of wate
klasskru [66]
Answer: The Millers need 15 gallons of water for 6 minutes.


Lets start by finding how much water is needed for 1 min shower. 
<span>
25 gallons of water is used for 10 min shower:

</span>10 mins = 25 gallons <span>

To find 1 min shower, we will divide the 25 gallons of water by 10. 
</span><span>
10 mins = 25 gallons            </span>← Divide by 10 on both sides<span>
÷ 10           ÷ 10
1 min = 2.5 gallons

Now that we know the Millers need 2.5 gallons for every 1 minute of shower, we can find 6 minutes of shower by multiplying by 6.

1 min = 2.5 gallons</span>         ← Multiply 6 on both sides<span>
   x6           x6
6 min = 15 gallons

-----------------------------------------------</span>---------------------------------------<span>
Answer: The Millers need 15 gallons of water for 6 minutes.
</span>--------------------------------------------------------------------------------------<span>

</span>
8 0
3 years ago
Question 7 )
soldier1979 [14.2K]

<em>Answer:</em>

<u>Tony</u> has 45 dollars  

<u>Milan</u> has 15 dollars

<u>Lucy</u> has 25 dollars

<em>Explanation:</em>

<u>Let </u><u><em>x</em></u><u> represent the amount of money Milan has in his wallet.</u>

TONY: 3x

MILAN: x

LUCY: x+10

<u>Lucy, Milan, and Tony have a total of $85 in their wallets. Hence, the following equation.</u>

<u />

3x+x+x+10=85

5x+10=85

5x=75

x=75/5

x=15

Tony has 45 dollars (3*15=45)

Milan has 15 dollars (x=15)

Lucy has 25 dollars (10+15=25)

7 0
3 years ago
A bicyclist traveled with a speed of 12 km/h from a camping ground to a station, located 60 km away. Write a formula expressing
yawa3891 [41]

1. The formula expressing the dependence of the variable s on t is: s = 60 - 12t

2. the distance travelled at time t = 3.5 h is 18 Km

<h3>What is speed? </h3>

Speed is the distance travelled per unit. Mathematically, it can be expressed as:

Speed = distance / time

<h3>1. How to determine the formula expressing the dependence of the variable s on t</h3>

From the question given, bicyclist traveled with a speed of 12 km/h from a camping ground to a station, located 60 km.

Thus, we shall determine the distance travel in time t as follow

  • Speed = 12 Km/h
  • Time = t
  • Distance in time t = ?

Speed = distance / time

12 = distance / t

Cross multiply

Distance = 12 × t

Distance in time t = 12t

But the total distance travelled is 60 Km. Thus, the remaining distance (s) from the bicyclist to the station at time (t) will be given as:

s = 60 - 12t

Thus, the formula expressing the dependence of the variable s on t is: s = 60 - 12t

<h3>2. How to determine the distance at t = 3.5 hours</h3>

The distance at t = 3.5 hours can be obtained as illustrated below:

  • Time (t) = 3.5 hours
  • Distance (s) = ?

s = 60 - 12t

s = 60 - (12 × 3.5)

s = 60 - 42

s = 18 Km

Thus, the distance travelled at t = 3.5 hours is 18 km

Learn more about speed:

brainly.com/question/680492

#SPJ1

6 0
2 years ago
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