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scoundrel [369]
3 years ago
11

Reflections need help 1 and two already done just need help on 3-11

Mathematics
1 answer:
eduard3 years ago
5 0

Step-by-step explanation:

-3 = -1

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73 divided by the difference between 12 and seven rewrite in number sentence
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One would rewrite this as:  73/(12-7)

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Stan is trying to pick out a name for his new puppy. He wants to know what the most common dog names are in his area. Which meth
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Survey of dog owners in the area in which he lives.
Finding the data specifically for the interested population is the best way here. only dog owners would be surveyed and choosing an area or radius in which he lives world work.
6 0
4 years ago
Find the area.<br> A. 19 ft²<br> B. 30 ft²<br> C. 31 ft²<br> D. 84 ft²
JulijaS [17]

Answer: D. 84 ft^2

Step-by-step explanation: The area of a trapezoid is (a+b)/2 x h. A and B are the bases, and h is the height. Plug in the numbers.

(8+16)/2 x 7 = 84

Your answer would be 84 ft^2. D.

8 0
4 years ago
Given that sin∅ = 1/4, 0 &lt; ∅ &lt; π/2, what is the exact value of cos∅?
Artemon [7]

Answer:

b

Step-by-step explanation:

Using the trigonometric identity

• sin²x + cos²x = 1 , hence

cosx = ± \sqrt{1-sin^2x}

cosΦ > 0 for 0 < Φ < \frac{\pi }{2}

cosΦ = \sqrt{1-(\frac{1}{4})^2 } = \sqrt{1-\frac{1}{16} } = \sqrt{\frac{15}{16} } = \frac{\sqrt{15} }{4} → b


3 0
3 years ago
Read 2 more answers
En la final de un concurso escolar de
Sati [7]

Usando la distribución hipergeométrica,  la probabilidad de que los alumnos del colegio A obtengan los dos premios (no hay empates), es: 0.2 = 20%.

<h3>¿Qué es la fórmula de distribución hipergeométrica?</h3>

La fórmula es:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

C_{n,x} = \frac{n!}{x!(n-x)!}

Los parámetros son:

  • x es el número de éxitos.
  • N es el tamaño de la población.
  • n es el tamaño de la muestra.
  • k es el número total de resultados deseados.

Los valores de los parámetros son:

N = 6, k = 3, n = 2.

La probabilidad de que los alumnos del colegio A obtengan los dos premios (no hay empates), es P(X = 2), por eso:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

P(X = 2) = h(2,6,2,3) = \frac{C_{3,2}C_{3,0}}{C_{6,2}} = 0.2

Puede-se aprender más a cerca de la distribución hipergeométrica en brainly.com/question/24826394

#SPJ1

4 0
2 years ago
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