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dexar [7]
3 years ago
6

one negative number is 4.5 more than another number. the sum of the squares of these numbers is 46.25. Find both

Mathematics
1 answer:
evablogger [386]3 years ago
8 0

Answer:

y = -6.5 and x = 2

Step-by-step explanation:

Let one negative number be -y and another number be x

We are given that one negative number is 4.5 more than another number

So, -y=x+4.5

We are also given that The sum of the squares of these numbers is 46.25.

So,x^2+(-y)^2=46.25\\x^2+(x+4.5)^2=46.25\\x^2+x^2+20.25+18x=46.25\\2x^2+18x=26.25\\x^2+9x=13.125\\x^2+9x-13.125=0\\

x=-6.5,2

When x = -6.5

-y=x+4.5

-y=-6.5+4.5

-y=-2

y=2

When x = 2

-y=x+4.5

-y=2+4.5

-y=6.5

y=-6.5

So, y = -6.5 and x = 2

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5 0
3 years ago
3 over 5 x minus 15 = 6 over 5 x plus 12
poizon [28]
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2 years ago
the sum of the digits of a two digit number is 7 if the digits are reversed the new number was increased by 3 equals 4 times the
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Answer:

16

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5 0
2 years ago
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julsineya [31]
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3 0
3 years ago
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7^3 times 7^-7 times 7
dusya [7]

Hello there! :)

<u><em>Answer:\frac{1}{343}</em></u>

<u><em>*The answer must have a fraction.*</em></u>

Step-by-step explanation:

Lesson: Zero and Negative Exponents.

Distributive property: a(b+c)=ab+ac

First, you apply exponent rule.

a^b*a^c=a^b^+^c

7^-^3

\frac{1}{7^3}=7^3=7*7*7=343

Final answer: \frac{1}{343}

Hope this helps!

Thanks!

-Charlie

Have a great day!

:)

:D

4 0
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