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serg [7]
3 years ago
9

Can anyone help with these two questions

Mathematics
1 answer:
Gala2k [10]3 years ago
6 0

Answer:

8)

9x+6=60 (Alternate angles)

9x=54

x=6

9)

13x-6=12x+1 (Vertically opposite angles 3 times)

13x=12x+7

x=7

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Three is what percent of eight
svet-max [94.6K]

Answer:

Step-by-step explanation:

x% of 8 = 3

x% = ⅜ =0.375 = 37.5%

3 is 37.5% of 8

3 0
3 years ago
If the equation y² - (K-<br>2y + 2k +1 = 0<br>with equal roots find the value of k​
777dan777 [17]

Answer:

y² - (K-  2)y + 2k +1 = 0

equal roots means D=0

D= b^2 - 4ac

a=1, b= (k-2), c= 2k+1

so,

(k-2)^2 - 4(1)(2k+1) = 0

=> k^2 +4 - 8k -4 = 0

=> k^2 -8k = 0

=> k^2 = 8k

=> k= 8k/k

=> k = 8

Therefore the answer is k= 8

Hope it helps........

8 0
3 years ago
A binary operation is defined on the set of real numbers ℝ by
zloy xaker [14]

Answer:

I. m = 2401

II. ((n+1) ∆ y)/n = 1/n[(n – y + 2)(n – y) + 1]

Step-by-step explanation:

I. Determination of m

x ∆ y = x² − 2xy + y²

2 ∆ − 5 = √m

2² − 2(2 × –5) + (–5)² = √m

4 – 2(–10) + 25 = √m

4 + 20 + 25 = √m

49 = √m

Take the square of both side

49² = m

2401 = m

m = 2401

II. Simplify ((n+1) ∆ y)/n

We'll begin by obtaining (n+1) ∆ y. This can be obtained as follow:

x ∆ y = x² − 2xy + y²

(n+1) ∆ y = (n+1)² – 2(n+1)y + y²

(n+1) ∆ y = n² + 2n + 1 – 2ny – 2y + y²

(n+1) ∆ y = n² + 2n – 2ny – 2y + y² + 1

(n+1) ∆ y = n² – 2ny + y² + 2n – 2y + 1

(n+1) ∆ y = n² – ny – ny + y² + 2n – 2y + 1

(n+1) ∆ y = n(n – y) – y(n – y) + 2(n – y) + 1

(n+1) ∆ y = (n – y + 2)(n – y) + 1

((n+1) ∆ y)/n = [(n – y + 2)(n – y) + 1] / n

((n+1) ∆ y)/n = 1/n[(n – y + 2)(n – y) + 1]

7 0
3 years ago
(2x^3-3x^2-19x+30)/(x-3)
NeX [460]

Answer:

2x^3 + 3x - 10

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Someone lmk what the answer is
Elodia [21]

f(-7) = -(-7)^2 - 10 \cdot (-7) + 16\\= -49 + 70 + 16\\= 22

7 0
4 years ago
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