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3 years ago

Can anyone help with these two questions

Mathematics

1 answer:

Gala2k [10]3 years ago

6 0

Answer:

$9x+6=60$ (Alternate angles)

$9x=54$

$x=6$

$13x-6=12x+1$ (Vertically opposite angles 3 times)

$13x=12x+7$

$x=7$

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3 years ago

If the sinø=7/12, what is cosø?

777dan777 [17]

Answer:

If the sinø=7/12, cosø is $\frac{\sqrt{95} }{12}$

Step-by-step explanation:

We are given sinФ = 7/12

We need to find cosФ

The basic trigonometric functions of right triangle are:

$sin\theta=\frac{opposite}{hypotenuse}$

$cos\theta=\frac{adjacent}{hypotenuse}$

We need values of adjacent and hypotenuse to find cosФ

Using Pythagoras theorem we can find the value of adjacent

$(Hypotenuse)^2= (Opposite)^2+(Adjacent)^2$

We have Hypotenuse= 12 and Opposite = 7 (because $sin\theta=\frac{opposite}{hypotenuse}$ and we are given $sin\theta=\frac{7}{12}$

Inserting values and finding adjacent:

$(Hypotenuse)^2= (Opposite)^2+(Adjacent)^2\\(12)^2=(7)^2+(Adjacent)^2\\144=49+(Adjacent)^2\\144-49=(Adjacent)^2\\95=(Adjacent)^2\\\sqrt{(Adjacent)^2} =\sqrt{95}\\Adjacent=\sqrt{95}$