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Vinil7 [7]
3 years ago
11

EASY MATH QUESTION FOR 20 PTS!!

Mathematics
2 answers:
WINSTONCH [101]3 years ago
4 0
THE ANSWER IS A. AND C.

Phoenix [80]3 years ago
4 0

The answer is B, C, A i just took the test

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Galina-37 [17]

Answer: C) 150°

Step-by-step explanation: all the angles are the same

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100 POINTS! WILL BE MARKED BRAINLIEST!!
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KE = 0 (because velocity is 0)  

PE = mgh = 2kg*9.8m/s^2*40m= 784 joule

<u>Explanation:</u>

KE stands for kinetic energy. In physics, the kinetic energy of an object is the energy that it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity.

Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes. Since in this case, the building is still and therefore it does not have any kind of kinetic energy because there is not acceleration.

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Sum term product factor quotients coefficients for 5x+12
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Y= x-8<br> y= 8 +x<br> What is the solution
tresset_1 [31]

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y=8-8

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Step-by-step explanation:

y=0

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When a cylindrical tank is filled with water at a rate of 22 cubic meters per hour, the level of water in the tank rises at a ra
Sergeu [11.5K]

Answer:

r=\sqrt{10}\text{ m}

Step-by-step explanation:

We have been given that when a cylindrical tank is filled with water at a rate of 22 cubic meters per hour, the level of water in the tank rises at a rate of 0.7 meters per hour. We are asked to find the approximate radius of tank in meters.

We will use volume of cylinder formula to solve our given problem as:

V=\pi r^2h, where,

r = Radius,

h = Height of cylinder.

Since the level of water in the tank rises at a rate of 0.7 meters per hour, so height of cylinder would be h = 0.7 meters at V=22\text{ m}^3.

Upon substituting these values in above formula, we will get:

22\text{ m}^3=\frac{22}{7}\cdot r^2(0.7\text{ m})

22\text{ m}^3=\frac{22}{10}\cdot r^2\text{ m}

\frac{10}{22}\cdot\frac{22\text{ m}^3}{\text{m}}=r^2

r^2=\frac{10}{22}\cdot\frac{22\text{ m}^3}{\text{m}}

r^2=10\text{ m}^2

Now, we will take positive square root of both sides as radius cannot be negative.

\sqrt{r^2}=\sqrt{10\text{ m}^2}

r=\sqrt{10}\text{ m}

Therefore, radius of tank would be approximately square root of 10 m.

5 0
2 years ago
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