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Aleks [24]
3 years ago
6

HELP ME!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
uysha [10]3 years ago
5 0

Answer:

it's G)

Step-by-step explanation:

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PLEASE QUICK HELP!!!
Fantom [35]

Answer:

4.5 / B

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Choose two values, a and b, each between 8 and 15. Show how to use the identity a^3+b^3=(a+b)(a^2-ab+b^2) to calculate the sum o
qaws [65]

Answer:

Step-by-step explanation:

a = 8

b  = 10

a^3 =8^3 = 512

b^3= 10^3 =1000

a^3 + b^3 = 1512

a^2 = 64

-ab = - 80

b^2 = 100

a + b=18

(a + b) (64 -  80+ 100)

18 * (84)

1512'

5 0
3 years ago
If AB = BC and BC = CD, then AB = CD
marta [7]

Answer:

correct

Step-by-step explanation:

8 0
3 years ago
A house worth $250,000 has a coinsurance clause of 90 percent. The owners insure the property for $191,250. They then have a fir
yan [13]

Answer: He will receive only $55080 against the fire insurance that caused damage the property.

Explanation:

Since we have given that a house worth $250,000 has a coinsurance clause of 90 percent .

But the owner insure the property for $191,250.

That means the owner does not insure the property for his full value ,

Amount incurred on fire that caused damage =$80,000

Amount he will receive against his insurance is given by

80000\times \frac{90}{100}\times \frac{191250}{250000}\\\\=\$55080

Hence, He will receive only $55080 against the fire insurance that caused damage the property.

4 0
3 years ago
Read 2 more answers
What is the x-coordinate of the midpoint of the segment whose endpoints are<br> (2, 3) and (-5, 5)?
ArbitrLikvidat [17]

Answer:

(-3/4, 4)

Step-by-step explaination:

add 2 and -5 then divide them by two and get

-1/2

then add 3 and 5 divide them by two and get

11/2

But as long as you remember that you're averaging the two points' x- and y-values, you'll do fine. It won't matter which point you pick to be the "first" point you plug in. Just make sure that you're adding an x to an x, and a y to a y.

so therefore the answer is (-3/4, 4)

7 0
3 years ago
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