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2 years ago

5

Susan joined a video rental club . She paid an initiation fee of $12.75, and it cost $0.75 per video that she rented . Write an

equation to show the total amount Susan paid to rent v videos

1 answer:

Anettt [7]2 years ago

6 0

Y=0.75v +12.75

y is the total cost, and v is the number of videos.

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Suki has 54 rock songs, 92 dance songs and 12 classical songs on her playlist. If Suki’s music player randomly selects a song fr

Ksenya-84 [330]

Answer:

92.4% or 73/79

Step-by-step explanation:

You have to add up all the individual songs, which is 158. Then add up the number of songs that aren't classical, which is 146. Then divide 146 by 158 which gives you your answer.

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2 years ago

Plzzz help i am ineeeddeddeedeededed of it!!!

Vikentia [17]

Sallys statement is always true
for example:
-6 + 2 = -4
but if I turn it around
2 - 6 = -4
same answer

-6 -6 = -12
swap around -6 - 6 = 12
same answer

again -3 + 6 = 3
and 6 - 3 = 3

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3 years ago

What’s the 5th term is 2,14,98

iragen [17]

$\bold{\huge{\orange{\underline{ Solution }}}}$

<h3><u>Correct </u><u>Question </u><u>:</u><u>-</u></h3>

What is the 5th term of an AP 2 , 14 ....98 .

<h3><u>Given </u><u>:</u><u>-</u><u> </u></h3>

<u>We </u><u>have </u><u> </u><u>AP</u><u>, </u>

$\sf{ 2 , 14 ,.... 98 }$
<u>AP </u><u>is </u><u>the </u><u>arithmetic </u><u>progression </u><u>or </u><u>a </u><u>sequence </u><u>of </u><u>numbers </u><u>in </u><u>which </u><u>succeeding </u><u>number </u><u>is </u><u>differ </u><u>from </u><u>preceeding </u><u>number </u><u>by </u><u>a </u><u>common </u><u>value</u><u>. </u>

<h3><u>Solution </u><u>:</u><u>-</u></h3>

<u>We </u><u>have </u><u>an </u><u>AP </u><u>:</u><u>-</u><u> </u><u>2</u><u> </u><u>,</u><u> </u><u>1</u><u>4</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>9</u><u>8</u>

<u>Therefore</u><u>, </u>

$\sf{a1\: or \:1st\: term = 2 }$
$\sf{a2 \:or \:2nd\: term = 14 }$
$\sf{an \:or\: last\: term = 98}$

<u>Here</u><u>, </u>

Common difference of an AP

$\sf{ a2 - a1 }$

$\sf{ = 14 - 2}$

$\sf{ = 12}$

Thus, The common difference is 12

<u>Now</u><u>, </u>

We know that,

$\sf{an = a1 + ( n - 1 )d}$

$\sf{a5 = 2 + ( 5 - 1 )12}$

$\sf{a5 = 2 + 4 × 12}$

$\sf{a5 = 2 + 48}$

$\sf{\red{a5 = 50}}$

Hence, The 5th term of given AP is 50

4 0

1 year ago

You have decided to wallpaper your rectangular bedroom. the dimensions are 12 feet 6 inches by 10 feet 6 inches by 8 feet 0 inch

Papessa [141]

The wall area is the product of the room perimeter and the room height:
A₁ = (2*(12.5 ft + 10.5 ft))*(8.0 ft) = 368 ft²

The window and door area together is
A₂ = 2*((4 ft)*(3 ft)) + (7 ft)*(3 ft) = 45 ft²

The area of one roll of wallpaper is
A₃ = (2.5 ft)*(30 ft) = 75 ft²

Then the number of rolls of wallpaper required will be
1.1*(A₁ - A₂)/A₃ ≈ 4.74

5 rolls of wallpaper should be purchased.

_____
As a practical matter, not much of the window and door area can be saved. The rolls are 30 inches wide, but the openings are 36 inches wide. Some will likely have to be cut from two strips. The strips will have to be the full length of the wall, and the amount cut likely cannot be used elsewhere. If the window and door area cannot be salvaged, then likely ceiling(5.4) = 6 rolls will be needed (still allowing 10% for matching and waste).

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2 years ago

Does the order pair (2,-8) satisfy the following function? y=-2x-5 Yes,No

Ludmilka [50]

No it doesn’t satisfy the function

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2 years ago