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Ksivusya [100]
3 years ago
12

Simplify the expression. 8+6x3-(20/2)^2

Mathematics
1 answer:
REY [17]3 years ago
8 0
<span>8 + 6 x 3 - (20/2)^2
</span><span>= 8 + 18 -(10)^2
</span>= 8 + 18 - 100
= -74

answer
- 74
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Write a quadratic function in vertex form whose graph has the vertex
ELEN [110]

Answer:

y = \frac{1}{2}(x - 5)² - 2

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k) = (5, - 2), thus

y = a(x - 5)² - 2

To find a substitute (7, 0) into the equation

0 = a(7 - 5)² - 2

0 = 4a - 2 ( add 2 to both sides )

2 = 4a ( divide both sides by 4 )

a = \frac{2}{4} = \frac{1}{2}

y = \frac{1}{2} (x - 5)² - 2 ← in vertex form

4 0
3 years ago
What is the range of the function in the graph?
Verdich [7]

The range of the function in the graph given can be expressed as: D. 20 ≤ s ≤ 100.

<h3>What is the Range and Domain of a Function?</h3>

All the possible set of x-values that are plotted on the horizontal axis (x-axis) are the domain of a function. In order words, they are the inputs of the function.

On the other hand, all the corresponding set of x-values that are plotted on the vertical axis (y-axis) are the range of a function. In order words, they are the outputs of the function.

In the graph given below that shows a function, s is plotted on the vertical axis (y-axis), and its values starts from 20, up to 100. The range can be said to be all values of s that are from 20 to 100.

Therefore, the range of the function in the graph given can be expressed as: D. 20 ≤ s ≤ 100.

Learn more about functions on:

brainly.com/question/15602982

#SPJ1

3 0
2 years ago
How do you do these questions?
Tanzania [10]

Answer:

μ ≈ 2.33

σ ≈ 1.25

Step-by-step explanation:

Each person has equal probability of ⅓.

\left[\begin{array}{cc}X&P(X)\\1&\frac{1}{3}\\2&\frac{1}{3}\\4&\frac{1}{3}\end{array}\right]

The mean is the expected value:

μ = E(X) = ∑ X P(X)

μ = (1) (⅓) + (2) (⅓) + (4) (⅓)

μ = ⁷/₃

The standard deviation is:

σ² = ∑ (X−μ)² P(X)

σ² = (1 − ⁷/₃)² (⅓) + (2 − ⁷/₃)² (⅓) + (4 − ⁷/₃)² (⅓)

σ² = ¹⁴/₉

σ ≈ 1.25

3 0
3 years ago
An aircraft​ (at Z) is spotted by two observers​ (at X and​ Y) who are L=1750 feet apart . As the airplane passes over the line
valentinak56 [21]

Answer:

at aircraft(at z) sported by

6 0
2 years ago
App 19.study
lions [1.4K]

Answer:

1 \to 22 \to 0.176

2 \to 13 \to 0.104

3 \to 18 \to 0.144

4 \to 29 \to 0.232

5 \to 37 \to 0.296

6 \to 6 \to 0.048

Step-by-step explanation:

Given

n = 125

See attachment for proper table

Required

Complete the table

Experimental probability is calculated as:

Pr = \frac{Frequency}{n}

We use the above formula when the frequency is known.

For result of roll 2, 4 and 6

The frequencies are 13, 29 and 6, respectively

So, we have:

Pr(2) = \frac{13}{125} = 0.104

Pr(4) = \frac{29}{125} = 0.232

Pr(6) = \frac{6}{125} = 0.048

When the frequency is to be calculated, we use:

Pr = \frac{Frequency}{n}

Frequency = n * Pr

For result of roll 3 and 5

The probabilities are 0.144 and 0.296, respectively

So, we have:

Frequency(3) = 125 * 0.144 = 18

Frequency(5) = 125 * 0.296 = 37

For roll of 1 where the frequency and the probability are not known, we use:

Total \ Frequency = 125

So:

Frequency(1) added to others must equal 125

This gives:

Frequency(1) + 13 + 18 + 29 + 37 + 6 = 125

Frequency(1) + 103 = 125

Collect like terms

Frequency(1) =- 103 + 125

Frequency(1) =22

The probability is then calculated as:

Pr(1) = \frac{22}{125}

Pr(1) = 0.176

So, the complete table is:

1 \to 22 \to 0.176

2 \to 13 \to 0.104

3 \to 18 \to 0.144

4 \to 29 \to 0.232

5 \to 37 \to 0.296

6 \to 6 \to 0.048

5 0
3 years ago
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