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zmey [24]
2 years ago
12

Mr. Ramirez class is playing a game in which students in a batch sticky notes that have an equivalent expression how can you sor

t the Expressions into groups?
Expressions:
10p-8
8p+2p-8
8(p+1)
3p+4p+6+5p
10p+4+2p+2
5p+8+3p
2(5p-4)
4(2p+2)
3(4p+2)
​
Mathematics
1 answer:
nadya68 [22]2 years ago
7 0

Brackets & Non Brackets

Step-by-step explanation:

You could sort them into equations with brackets and equations without brackets

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Please help! I’m on a timer :/
weqwewe [10]

If you want to find out how Addision paid each month, you have to have 36, then divide 36 by 12, and the answer will give you 3. So Addison paid $3 every month.

Hope this Helped

Nate

4 0
2 years ago
Read 2 more answers
I need some help with geometry?​
kramer
39=9x+7-3x+20

Subtract 27 from each side

12=6x
2=x

Now plug in 2 for x to find AB and BC

9x+7= AB
9(2)+7=AB
18+7= AB
25= AB

-3x+20= BC
-3(2)+20= BC
-6+20= BC
14= BC
3 0
2 years ago
The sum of a two digit number and the number obtained by interchanging the digits is 132. If the two digits differ by 2, find th
damaskus [11]

Answer:

A two-digit number can be written as:

a*10 + b*1

Where a and b are single-digit numbers, and a ≠ 0.

We know that:

"The sum of a two-digit number and the number obtained by interchanging the digits is 132."

then:

a*10 + b*1 + (b*10 + a*1) = 132

And we also know that the digits differ by 2.

then:

a = b + 2

or

a =  b - 2

So let's solve this:

We start with the equation:

a*10 + b*1 + (b*10 + a*1) = 132

(a*10 + a) + (b*10 + b) = 132

a*11 + b*11 = 132

(a + b)*11 = 132

(a + b) = 132/11 = 12

Then:

a + b = 12

And remember that:

a = b + 2

or

a = b - 2

Then if we select the first one, we get:

a + b = 12

(b + 2) + b = 12

2*b + 2 = 12

2*b = 12 -2 = 10

b = 10/2 = 5

b = 5

then a = b + 2= 5 + 2 = 7

The number is 75.

And if we selected:

a = b - 2, we would get the number 57.

Both are valid solutions because we are changing the order of the digits, so is the same:

75 + 57

than

57 + 75.

6 0
3 years ago
How would I go about solving this problem???
schepotkina [342]
So.. if you take a peek at the picture below

the trunk is really just a half-cylinder on top of a square, with a depth of 2 meters

what's the volume?   well, easy enough, take the volume of the cylinder, then half it
take the volume of the rectangular prism, and then add them both

\bf \textit{volume of a cylinder}\\\\

\begin{array}{llll}
C=\pi r^2 h\\\\
\textit{half that}\\\\
\cfrac{\pi r^2 h}{2}
\end{array}\qquad 
\begin{cases}
r=radius\\
h=height\\
-------\\
r=\frac{1}{2}\\
h=2
\end{cases}\implies \cfrac{C}{2}=\cfrac{\pi \left(  \frac{1}{2}\right)^2 2}{2}\\\\
-----------------------------\\\\
\textit{volume of a square}\\\\
V=lwh\qquad 
\begin{cases}
l=length\\
w=width\\
h=height
----------\\
l=1\\
w=1\\
h=2
\end{cases}\implies V=2



now.. for the surface area... \bf \textit{surface area of a cylinder}\\\\
\begin{array}{llll}
S=2\pi r(h+r)\\\\
\textit{half that}\\\\
\cfrac{2\pi r(h+r)}{2}
\end{array}\begin{cases}
r=radius\\
h=height\\
-------\\
r=\frac{1}{2}\\
h=2
\end{cases}

now.. for the surface area of the prism... well

is really just 6 rectangles stacked up to each other at the edges

so... get the area of the lateral rectangles, and the one at the bottom, skip the rectangle atop, because is the one overlapping the cylinder, and is not outside, and thus is not surface area then

for the lateral ones, you have a front of 1x1, a back of 1x1 and a left of 1x2 and a right of 1x2, and then the one at the bottom, which is a 1x2

then add both surface areas, and that's the surface area of the trunk

5 0
3 years ago
How many times can 7 go into 6437?
asambeis [7]
About 9-10 times(when you divide you get a decimal)

3 0
3 years ago
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