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vlada-n [284]
1 year ago
9

Help would be greatly appreciated :)

Mathematics
1 answer:
Phantasy [73]1 year ago
5 0

Answer:

D= -0.37

R= -0.34

Step-by-step explanation:

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Can someone help me with this
jarptica [38.1K]

The answer is:

x=-8

Because:

If you pick a number(-8) to fill in the equation written below

5x+20+5x=5x-20

After applying the -8 to x you get

-40+20-40=-40-20

When you simply the both sides you get

-60=-60

And that’s right -60 is equal to -60!

5 0
3 years ago
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Find the value of X.
tatuchka [14]
This is the correct answer

4 0
1 year ago
Write a quadratic function for each graph described.
user100 [1]

Answer:

y=2x^2-\frac{4}{3}x-\frac{10}{3}

Step-by-step explanation:

we know that

The roots of the quadratic function (x-intercepts) are

x=-1 and x=5/3

so

we can write the equation of the parabola as

y=a(x+1)(x-\frac{5}{3})

where

a is a coefficient

Remember that

The parabola pass through the point (5,40)

substitute the value of x and the value of y of the ordered pair in the quadratic equation and solve for a

x=5, y=40

40=a(5+1)(5-\frac{5}{3})

40=a(6)(\frac{10}{3})

40=20a\\a=2

substitute

y=2(x+1)(x-\frac{5}{3})

apply distributive property

y=2(x^2-\frac{5}{3}x+x-\frac{5}{3})\\\\y=2(x^2-\frac{2}{3}x-\frac{5}{3})\\\\y=2x^2-\frac{4}{3}x-\frac{10}{3}

see the attached figure to better understand the problem

6 0
3 years ago
When simplified and written in standard form, which quadratic function is equivalent to the polynomial shown?
mars1129 [50]

Answer:

2c^2 - 2c - 3

Step-by-step explanation:

Next time, please share the answer choices.  Thank you.

Group together the 'c' terms in 2 + 7c – 4c2 – 3c + 4:

                                                     2  + 4c and -4c^2 + 4  Then we have:

-4c^2 + 4c + 6

We should reduce this by factoring -2 out of all three terms:

2c^2 - 2c - 3  This is the desired quadratic in standard form.

3 0
2 years ago
When a number is increased by 40 % it gives 84. Find the original number
Julli [10]
I believe the answer is $33.60?
3 0
3 years ago
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