Question

Peter’s teacher says he may have his report card percentage based on either the mean or the median and he can drop one test score if he chooses. 84%, 71%, 64%, 90%, 75%, 44%, 98% Which measure of center should Peter choose so he can have the highest percentage possible?

Answer 1

Answer:

It would be best if Peter's report card percentage was based on the mean and if he could drop a percent, he should drop the 44%.

Step-by-step explanation:

The median (without dropping a score) of this set would be 75%

( 44%, 64%, 71%, 75%, 84%, 90%, 98% )

The mean (without dropping a score) of this set would be 75.1428571%

526 ÷ 7 = 75.14 ( 75.1428571 )

Answer 2

Answer:

Go with the mean and remove the lowest score

Step-by-step explanation:

84%, 71%, 64%, 90%, 75%, 44%, 98%

First find the mean, which is add all the numbers and divide by the number of numbers

(84+ 71+ 64+ 90+ 75+ 44+98)/7

526/7 =75.14

If we drop one score, we would drop the lowest

(84+ 71+ 64+ 90+ 75+98)/6

482 /6 = 80.33

If we use the median, we take the middle, so put the scores from lowest to highest

44%,  64%,71%,     75%,      84%,90% , 98%

Without removing a score the median is  75%

Removing the lowest score

 64%,71%,     75%,      84%,90% , 98%

The median is between 75 and 84

(75+84)/2 = 79.5 %