If the length of a rectangle is a two-digit number with identical digits and the width is 1/10 the length and the perimeter is 2 times the area of the rectangle, what is the the length and the width
Solution:
Let the length of rectangle=x
Width of rectangle=x/10
Perimeter is 2(Length+Width)
= 2(x+x/10)
Area of Rectangle= Length* Width=x*x/10
As, Perimeter=2(Area)
So,2(x+x/10)=2(x*x/10)
Multiplying the equation with 10, we get,
2(10x+x)=2x²
Adding Like terms, 10x+x=11x
2(11x)=2x^2
22x=2x²
2x²-22x=0
2x(x-11)=0
By Zero Product property, either x=0
or, x-11=0
or, x=11
So, Width=x/10=11/10=1.1
Checking:
So, Perimeter=2(Length +Width)=2(11+1.1)=2*(12.1)=24.2
Area=Length*Width=11*1.1=12.1
Hence, Perimeter= 2 Area
As,24.2=2*12.1=24.2
So, Perimeter=2 Area
So, Answer:Length of Rectangle=11 units
Width of Rectangle=1.1 units
Answer:
No solutions. You can’t have a negative absolute value.
Answer:
$3.42
Step-by-step explanation:
Meters of material required = 1.2 meters
Cost per meter of material = $0.85
Direct labor hours = 0.1
Cost of direct labor per hour = $15
Overhead rate = $9 per direct labor hour
Standard cost per unit of product :
(Direct material cost per unit + direct labor cost per unit + overhead cost per unit)
Direct material cost per unit :
Material needed × cost per meter = (1.2 × $0.85) = $1.02
Direct labor cost per unit :
Direct labor hour × cost per hour = ( 0.1 × $15) = $1.5
Overhead cost:
0.1 * $9 = $0.9
Standard cost :
($1.02 + $1.5 + $0.9) = $3.42
Answer:-3
Step-by-step explanation:
