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pychu [463]
3 years ago
14

a pool is the shape of a rectangle has a perimeter of 80 feet. The pool is 8 feet less wide than it is long. Find the length and

width of the pool.
Mathematics
1 answer:
Salsk061 [2.6K]3 years ago
7 0

Answer:

Length= 24 feet

Width= 16 feet

Step-by-step explanation:

Equation 1) Perimeter = 2L+2W

Equation 2) Perimeter = 80

Equation 3) L-8=W

1) Substitute L-8 as W in the first equation, and 80 as the Perimeter:

2L+2(L-8)=80

2) Distribute 2 to L and -8:

2L+2L-16=80

3) Add 16 to both sides, and combine alike terms:

4L=96

4) Divide both sides by 4:

L=24

5) Substitute 24 as L in the third equation:

24-8=W

6) Solve:

W=16

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F(x) = 4x+3x<br> g(x) = 2x-5<br> 7. Find (f+9) (x) <br> 8. Find (f - g) (x)
notka56 [123]

Answer:

7. (f+g)(x) = 6x - 2

8. (f-g)(x) = 2x + 8

Step-by-step explanation:

We are given two function, f(x) and g(x).

We want to find their addition and their subtraction, and we do this combining like terms.

The functions are:

f(x) = 4x + 3

g(x) = 2x - 5

7. Find (f+9) (x)

4x + 3 + 2x - 5 = 4x + 2x + 3 - 5 = 6x - 2

So

(f+g)(x) = 6x - 2

8. Find (f - g) (x)

4x + 3 - (2x - 5) = 4x + 3 - 2x + 5 = 4x - 2x + 3 + 5 = 2x + 8

So

(f-g)(x) = 2x + 8

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2 years ago
Something for which someone is responsible and it "takes money out of the pocket" is called a/an
DiKsa [7]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
your planning to build a boat. you have a sample board of wood that you want to use . the board has an area of 1/3 ft squared an
frosja888 [35]
Given:
Area of sample board: 1/3 square ft.
Weight of sample board: 1/5 lbs

We need to get the weight of the whole square foot.

1/3 square foot is only a part of the whole square foot. Its corresponding weight is 1/5 pounds. We need to divide the area by its corresponding weight to get the total weight per square foot.

1/3 ÷ 1/5 

Rules of dividing fractions:
1st fraction: 1/3 ; 2nd fraction: 1/5

1) Get the reciprocal of the 2nd fraction. 1/5 ⇒ 5/1

2) Multiply 1st fraction to the reciprocal of the 2nd fraction
1/3 * 5/1 = 5/3

3) Simplify fraction.
5/3 is an improper fraction. To simplify it, it needs to become a mixed fraction.

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8 0
3 years ago
PLEASE HELP ME IVE POSTED THIS 765678 AND STILL NO RESPONSE
Debora [2.8K]

Problem 1

<h3>Answer:  6.7</h3>

----------------

Work Shown:

The two points are (x_1,y_1) = (1,-2)  and (x_2,y_2) = (4,4)

Apply the distance formula to get the following

d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(1-4)^2 + (-2-4)^2}\\\\d = \sqrt{(-3)^2 + (-6)^2}\\\\d = \sqrt{9 + 36}\\\\d = \sqrt{45}\\\\d \approx 6.7082039\\\\d \approx 6.7\\\\

The distance between the two endpoints is roughly 6.7 units. This is the same as saying the segment is roughly 6.7 units long.

======================================================

Problem 2

<h3>Answer:  3.6</h3>

----------------

Work Shown:

We'll use the distance formula here as well.

This time we have the two points (x_1,y_1) = (3,1) and (x_2,y_2) = (5,-2)

The distance between them is...

d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(3-5)^2 + (1-(-2))^2}\\\\d = \sqrt{(3-5)^2 + (1+2)^2}\\\\d = \sqrt{(-2)^2 + (3)^2}\\\\d = \sqrt{4 + 9}\\\\d = \sqrt{13}\\\\d \approx 3.6055513\\\\d \approx 3.6\\\\

This distance is approximate.

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2 years ago
Given: ABCD ∥gram, BK ⊥ AD , AB ⊥ BD AB=6, AK=3 Find: m∠A, BK, AABCD
jenyasd209 [6]

1. Consider right triangle ABK. The hypotenuse AB is 6 un. and the leg AK is 3 un. Since the leg is half of the hypotenuse, then the opposite to the leg angle is 30°. This means that m∠ABK=30°. Then m∠BAK=90°-30°=60°.

2. By the Pythagorean theorem,

AB^2=AK^2+BK^2,\\\\6^2=3^2+BK^2,\\\\BK^2=36-9,\\\\BK^2=27,\\\\BK=3\sqrt{3}\ un.

3. Consider right triangle ABD. In this triangle AD is hypotenuse and m∠ADB=90°-m∠BAD=90°-60°=30°. Then the leg AB opposite to the angle 30° is half of the hypotenuse and AD=12 un.

4. The area of parallelogram is

A_{ABCD}=AD\cdot BK=12\cdot 3\sqrt{3}=36\sqrt{3}\ sq. un.

5 0
2 years ago
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