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zzz [600]
3 years ago
10

A developer wants to develop a 25-acre subdivision. He figures that the streets and common area will take up about 35% of this o

verall area. If the minimum lot size is to be 25,000 SF, how many lots can the developer have on this property?
Mathematics
1 answer:
lys-0071 [83]3 years ago
5 0
There are 43560 SF in an acre first you want to find the total SF witch is 43560x25=1089000 SF. also the common area will take up about 35% of the overall area so do .35x1089000=381,150 and subtract that from the overall SF witch gives you 707,850 then divide this by 25000 SF for the total number of lots that the developer can have on this property witch is 28 or 28.3 rounded to the tenths.

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What is the sum of the first 75 even numbers starting with 2? Enter your answer in the box.
vova2212 [387]

Answer:

5700

Step-by-step explanation:

step 1 Address the formula, input parameters & values.

Input parameters & values:

The number series 2, 4, 6, 8, 10, 12, .  .  .  .  , 150.

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step 2 apply the input parameter values in the AP formula

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= (75 x 152)/ 2

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6 0
3 years ago
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Solve the equations and graph the solution
jenyasd209 [6]

Given:

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The solution for the given inequalities and graph the solution.

Solution:

We have,

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Solve the above inequalities separately.

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Divide both sides by -5.

x>\dfrac{-3}{-5}

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And,

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x

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From (i) and (ii). we get

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The graph of the solution is shown below.

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