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zzz [600]
3 years ago
10

A developer wants to develop a 25-acre subdivision. He figures that the streets and common area will take up about 35% of this o

verall area. If the minimum lot size is to be 25,000 SF, how many lots can the developer have on this property?
Mathematics
1 answer:
lys-0071 [83]3 years ago
5 0
There are 43560 SF in an acre first you want to find the total SF witch is 43560x25=1089000 SF. also the common area will take up about 35% of the overall area so do .35x1089000=381,150 and subtract that from the overall SF witch gives you 707,850 then divide this by 25000 SF for the total number of lots that the developer can have on this property witch is 28 or 28.3 rounded to the tenths.

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Solve for x please 2/3 x+1 =27
romanna [79]

2/3 x + 1 = 27

subtract 1 from each side

2/3 x = 26

multiply by 3/2

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A person bought some Australian dollar of NRs 1,50,000 according to the exchange rate. Australian dollar 1 = NRs 77.02. After fi
AlekseyPX

Answer:

  5.26% profit (NRs 7,894.24)

Step-by-step explanation:

The exchange of 1,50,000 NRs to A$ will give ...

  A$ 1/(NRs 77.02) = x /1,50,000

  x = A$ 1,50,000/77.02 = A$ 1947.54 . . . . . (rounded down)

If the Nepali rupees are devalued by 5%, then what did buy A$ 1 will now buy only A$ 0.95. Then the exchange back to NRs will give ...

  (NRs 77.02)/(A$ 0.95) = x/(A$ 1947.54)

  x = NRs (1947.54)(77.02/0.95) = NRs 1,57,894.24

The effective profit is the difference from the amount initially exchanged, NRs 7,894.24, or ...

  (1,57,984.24/1,50,000 -1) × 100% ≈ 5.26%

__

<em>Additional comment</em>

Except for the loss in the exchange due to rounding down, the profit would be 1/0.95 -1 = 5.2632%. Instead, it is 5.2628%. This is why investors move their money to investments that retain their value when the local currency is losing its value.

5 0
2 years ago
Write the recursive formula for 16,23,30,37
4vir4ik [10]

Answer:

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Step-by-step explanation:

Arithmetic Sequence

4 0
2 years ago
HELP ME ON THIS PLEASE!!!! SHOW WORK!!!!
Mumz [18]

Answer:

<h2>1. x = 4</h2><h2>2. x = 20</h2>

Step-by-step explanation:

1.

ΔABC and ΔAJK are similar (AA). Therefore the sides are in proportion:

\dfrac{AC}{AJ}=\dfrac{AB}{AK}

We have:

AC = 1 + 4 = 5

AJ = 1

AB = 1 + x

AK = 1

Substitute:

\dfrac{5}{1}=\dfrac{1+x}{1}

5=1+x           <em>subtract 1 from both sides</em>

4=x\to x=4

2.

ΔVUT and ΔVMN are similar (AA). Therefore the sides are in proportion:

\dfrac{VU}{VM}=\dfrac{VT}{VN}

We hve:

VU = x + 8

VM = x

VT = 49

VN = 49 - 14 = 35

Substitute:

\dfrac{x+8}{x}=\dfrac{49}{35}              <em>cross multiply</em>

35(x+8)=49x          <em>use the distributive property a(c + b) = ab + ac</em>

35x+280=49x              <em>subtract 35x from both sides</em>

280=14x         <em>divide both sides by 14</em>

20=x\to x=20

3 0
3 years ago
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