Leena consumes 400 cal at breakfast and 350 cal at lunch. She consumes 2/3 of her daily calories at dinner. If X represents the calories consumed at dinner, which statements describe the situation? Check all that apply. Lena consumed 1500 cal at dinner. Do you equation 2/3 (x+400+350)=x can be used to model the situation. Lena consumed 500 cal at dinner. Lena consumed 1000 cal at dinner. The equation 2/3(x)=x(400+350) can be used to model the situation. The equation 2/3x(400+350)=x Can’t be used to model the situation
2 answers:
Answer:
The answer above is confusing and incorrect, the correct answer is A and B. The answers are contradicting, though it is somewhat explained.
Step-by-step explanation:
1) Data: Meal calories consumed Breakfast 400 cal Lunch 350 cal Dinner x ------------------ Total 400 + 350 + x = 750 + x 2) Equation: <span> She consumes 2/3 of her daily calories at dinner => (2/3)[750+x] = x 3) Analyze each statement: </span><span>a) Lena
consumed 1500 cal at dinner. Solve the equation to find if the statement is true: </span> <span><span>(2/3)[750+x] = x </span>2(750+x) = 3x 1500 + 2x = 3x 1500 = 3x - 2x x = 1500 Conclusión: TRUE stament. b) Do you equation 2/3 (x+400+350)=x can be
used to model the situation. That is the same equation that I found above. Conclusion: TRUE statement c) Lena consumed 500 cal at dinner. She consumed (2/3) * 1500 = 500 cal Conclusion: TRUE statement d) Lena
consumed 1000 cal at dinner. No, we calculated that she consumed 500 cal at dinner. Conclusion: FALSE statement e) The equation 2/3(x)=x(400+350) can be used
to model the situation. No: (2/3) x = 500 and x(400+350) = 500*750 = 375,00, which are not equal. Conclusion: FALSE statement. f) The equation 2/3x(400+350)=x Can’t be used to
model the situation
No: in that equation the variable x cancels out because it appears a factor at both sides. </span>Conclusion: TRUE statement
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