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3 years ago

URGENT Solve 2(4 x + 3) < 5 x + 21. { x | x < 9} { x | x > -5} { x | x > -9} { x | x < 5}

Mathematics

1 answer:

zmey [24]3 years ago

6 0

Answer:

{ x | x < 5}

Step-by-step explanation:

2(4 x + 3) < 5 x + 21

8x + 6 < 5x + 21

3x < 15

x < 5

Answer

{ x | x < 5}

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monitta

Answer:

a) x+3x/2y or (3x+2xy)/2y

b) b^12

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Step-by-step explanation:

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2 years ago

A recipe for chicken noodle soup is shown.

gogolik [260]

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2 years ago

Ten less than five times a number is less than six times the number decreased by eight

Luden [163]

10 - 5x < 6x - 8

We can treat this inequality like a normal algebraic equation.

Add 5x to both sides

10 < 11x - 8

Add 8 to both sides

18 < 11x

Divide both sides by 11

1.64 < x

X is greater than the value 1.64.

Let's plug the number 2 into each value of x to verify.

10 - 5x < 6x - 8

10 - 5*2) < (6 * 2) - 8

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0 < 4

It's correct.

Now let's plug 1, which is less than 1.64.

10 - 5x < 6x - 8

10 - 5 < 6 - 8

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This is not correct, which means that our answer was correct.

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3 years ago

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Ainat [17]

Answer:

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3 years ago

A rather flimsy spherical balloon is designed to pop at the instant its radius has reached 3 centimeters. Assuming the balloon i

Anni [7]

Answer:

The radius is growing at the rate of 0.09 centimeter per second at the instant it pops.

Step-by-step explanation:

We are given the following information in the question:

A spherical balloon is designed to pop at the instant its radius has reached 3 centimeters.

The balloon is filled with helium at a rate of 10 cubic centimeters per second .

$\displaystyle\frac{dV}{dt} = 10~cm^3/sec.$

We have to find fast the radius is growing at the instant it pops.

Volume of spherical balloons =

$\displaystyle\frac{4}{3}\pi r^3$

Differentiating, we get,

$\displaystyle\frac{dV}{dt} = \frac{4}{3}\pi 3r^2 \displaystyle\frac{dr}{dt} = 4\pi r^2 \displaystyle\frac{dr}{dt}$

Putting the values, we get,

$10 = 4\times 3.14\times (3)^2\times \displaystyle\frac{dr}{dt}\\\\\frac{dr}{dt} = \frac{10}{4\times 3.14\times (3)^2} = 0.0884 \approx 0.09\\\\\frac{dr}{dt} = 0.09\text{ centimeter per second}$

The radius is growing at the rate of 0.09 centimeter per second at the instant it pops.

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2 years ago