Answer:
I need more context ,like the graph to figure this out.
Step-by-step explanation:
Answer:
4,400,073
Step-by-step explanation:
Ez
Answer:
In order to find the variance we need to calculate first the second moment given by:
And the variance is given by:
![Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924](https://tex.z-dn.net/?f=%20Var%28X%29%20%3D%20E%28X%5E2%29%20%2B%5BE%28X%29%5D%5E2%20%3D%2023.36%20-%5B4.74%5D%5E2%20%3D%200.8924)
And the deviation would be:
Step-by-step explanation:
Previous concepts
The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.
The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).
Solution to the problem
For this case we have the following distribution given:
X 3 4 5 6
P(X) 0.07 0.4 0.25 0.28
We can calculate the mean with the following formula:
In order to find the variance we need to calculate first the second moment given by:
And the variance is given by:
And the deviation would be:
Answer:
decreasing
Step-by-step explanation:
"Increasing" means the graph is going up from left to right.
"Decreasing" means the graph is going down from left to right.
"Constant" means the graph is "flat" (this is not a technical term) it is keeping the same y value, neither going up nor going down.
What can be super confusing is the
(2.2, 5) mentioned in the question. THIS IS NOT A POINT. It is an interval and points and intervals unfortunately have the same notation sometimes.
An "interval" is a section of the graph, here: FROM 2.2 not including 2.2, TO 5 not including 5. These are like the address on the x-axis. If you look at your graph at 2.2 on the x-axis, it is a peak(relative maximum) and it goes down to the right to where x is 5 where it bottoms out (relative minimum) So on that interval, from 2.2 to 5, the graph is DECREASING.
