Answer:
the probability that a randomly selected U.S. adult weighs less than the overweight(but not obese) is 0.394
Step-by-step explanation:
Given the data in the question;
Underweight Healthy Weight Overweight (not Obese) Obese
Probability 0.017 0.377 0.343 0.263
so
P( underweight) = 0.017
P( Healthy Weight) = 0.377
P( Overweight (not Obese) ) = 0.343
P( Obese ) = 0.263
now, the probability that a randomly selected U.S. adult weighs less than the overweight(but not obese) range will be;
P( weigh less than overweight(but not obese) = P( underweight) + P( Healthy Weight)
P( weigh less than overweight(but not obese) = 0.017 + 0.377
P( weigh less than overweight(but not obese) = 0.394
Therefore, the probability that a randomly selected U.S. adult weighs less than the overweight(but not obese) is 0.394
This equation can be solved graphically by plotting the equations
f(x) = 3^x
and
g(x) = 5x-1.
The x-coordinate of the point(s) of intersection is the solution.
_____
On my graphing calculator, I find it easier to locate x-intercepts, so I would rewrite the equation as
3^x -(5x -1) = 0
and plot the function
h(x) = 3^x -(5x -1)
The x-intercept(s) would be the solutions. (There are two: x≈0.577, x=2.)
Answer: 3 + 7i
Step-by-step explanation:
Equation expanded: 12 + 5i - 9 + 2i // now simplfy
12 - 9 = 3
5i + 2i = 7i
// together, we get
3 + 7i
Answer: If its .05 cents then only 20 cents to finish the collection I got that because 51 - 47= 4 and if it is .05 cents then I did 4 * 5 = 20
Answer:
5 minutes.
Step-by-step explanation:
We have been given that a bank finds that the average number of people waiting in line during lunch hour is 10. On average, during this period, 2 people per minute leave the bank after receiving service.
We will use flow time formula to solve our given problem.


Therefore, on average bank customers wait in line for 5 minutes.