Question

A bag contains 6 blue balls, 3 green balls and 3 yellow balls. What is the probability of choosing one blue ball and then a yellow ball with replacement?

Answer 1

Prob(first ball being  blue) =  6 / (6 + 3 + 3) = 6/12 = 1/2
Prob ( picking a yellow ball) = 3 /12 = 1/4

As the 2 events are independent the probabilities are multiplied 
So the answer is 1/2 * 1/4 = 1/8

Answer 2

Answer:

1/8

I just took this test and this is the correct answer! Good luck!!