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fiasKO [112]
3 years ago
5

15. The container shown in the figure is filled with a liquid that weighs 50 g. Find its density.

Mathematics
2 answers:
3241004551 [841]3 years ago
5 0

Answer:

  C.  0.006 g/cm³

Step-by-step explanation:

As the units tell you, density is the ratio of mass to volume. The volume of the container is found from ...

  V = πr²h = π(10 cm)²(25 cm) = 2500π cm³

Then the density is ...

  ρ = (50 g)/(2500π cm³) = 1/(50π) g/cm³

  ρ ≈ 0.006 g/cm³

_____

<em>Comment on the problem</em>

The "liquid" has about the same density as air pressurized to 75 psi.

Shalnov [3]3 years ago
5 0

Can someone confirm is this answer is right?

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A weather service records 28.8 inches of rain over a 12 month period. What is the average rainfall per month for the year?
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For which of the following is x=-5 a solution. Select all that apply
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A software designer is mapping the streets for a new racing game. all of the streets are depicted as either perpendicular or par
ElenaW [278]

The equation of the central street PQ is  -1.5x - 3.5y = -31.5 option (b) is correct.

<h3>What is a straight line?</h3>

A straight line is a combination of endless points joined on both sides of the point.

We have a straight line:

-7x+3y=-21.5  

Convert it to the general form given below:

\rm y=mx+c

\rm 3y=-21.5+7x\\\\ \rm y = \frac{-21.5}{3}+\frac{7}{3}x or

\rm y = \frac{7}{3}x-\frac{21.5}{3}

m = \frac{7}{3}   (Slope of AB line)

For the slope(m') of the PQ line:

\rm m'=-\frac{1}{m}    ( because AB and PQ are perpendicular to each other)

\rm m' = -\frac{3}{7}

We know the:

\rm (y-y')=m'(x-x')

Where (x', y') = (7, 6), we get:

\rm (y-6)=-\frac{3}{7} (x-7)

\rm 7(y-6)=-3 (x-7)\\\\\rm 7y-42= -3x+21\\\\\rm 7y= -3x+21+42\\\\\rm 3x+7y=63

\rm -1.5x-3.5y=-31.5   (multiply by -1/2 on both sides)

Thus, the equation of the central street PQ is  -1.5x - 3.5y = -31.5

Learn more about the straight line.

brainly.com/question/3493733

6 0
2 years ago
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