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fiasKO [112]
3 years ago
5

15. The container shown in the figure is filled with a liquid that weighs 50 g. Find its density.

Mathematics
2 answers:
3241004551 [841]3 years ago
5 0

Answer:

  C.  0.006 g/cm³

Step-by-step explanation:

As the units tell you, density is the ratio of mass to volume. The volume of the container is found from ...

  V = πr²h = π(10 cm)²(25 cm) = 2500π cm³

Then the density is ...

  ρ = (50 g)/(2500π cm³) = 1/(50π) g/cm³

  ρ ≈ 0.006 g/cm³

_____

<em>Comment on the problem</em>

The "liquid" has about the same density as air pressurized to 75 psi.

Shalnov [3]3 years ago
5 0

Can someone confirm is this answer is right?

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On a coordinate plane, what is the distance between (-7, 3) and (2,3)?
Angelina_Jolie [31]

Answer:

The distance is 9

Step-by-step explanation:

Distance formula: \sqrt{(x_{2}-x_{1} )^{2}+(y_{2} -y_{1})^2   }

Plug in the points:

\sqrt{(2-(-7))^{2}+(3-3)^2   } = \sqrt{(9)^{2}+(0)^2   } = \sqrt{(9)^2} = 9

7 0
3 years ago
A farmer feeds her four horses 64 bales of hay each week. How many bales of hay would the farmer need in order to feed six horse
jekas [21]

Answer:

96 bales

Step-by-step explanation:

\frac{64}{4} = \frac{x}{6}

You must multiply 6 by 64, which is 384.

Then you divide that by 4, which is 96.

Therefore, the answer is 96.

Also, I lined up the bales in the same row and horses in the same row, so this way can help. It can also help if it's in the same column though, but I hope this helped you!

5 0
3 years ago
Read 2 more answers
Bruce is going to call one person from his contacts at random. He has 25 total contacts. 20 of those contacts are from his neigh
Naya [18.7K]
<h3>P(call a person not from his neighborhood) = (\frac{1}{5} )</h3>

Step-by-step explanation:

Here, the total number of contacts in the list if Bruce  = 25 contacts

The total number of neighbors in the contact = 20 people

Now, let E: Event of calling a person from his neighborhood

So, P(E) = \frac{\textrm{Total Favorable Outcomes}}{\textrm{Total Outcomes}}  = \frac{20}{25} = (\frac{4}{5})

So, the probability of calling a person from his neighborhood  is (\frac{4}{5} )

⇒P(E) = (\frac{4}{5} )

Now,as we know: P(E)  + P(not E) = 1

So, the probability of NOT calling a person from neighborhood

= 1 -  probability of calling a person from his neighborhood

= 1 - (\frac{4}{5}) = \frac{5-4}{5}   = (\frac{1}{5})

⇒P( not E) = (\frac{1}{5} )

Hence,  P(call a person not from his neighborhood) = (\frac{1}{5} )

5 0
3 years ago
Read 2 more answers
Part A
kkurt [141]

Answer:

Part A: A  

Part B: A

Step-by-step explanation:

1)

the inequality should be less than or equal to, since we need to find how many are left

now, the answer B is wrong, since there can't be negative 56, since Xander collected some cans, though he still must collect a few

thus, the answer is A

2)

A again is correct, since it represents:c ≤ 56

B represents c ≥ 56

C represents c ≤ –56

D represents c ≥ -56

3 0
4 years ago
Find the flux of F = x^3 i  + y^3 j  + z^3k through the closed surface bounding the solid region x^2 + y^2 ≤ 4, 0 ≤ z ≤ 4
givi [52]
Use the divergence theorem. Let R be the cylindrical region, then

\displaystyle\iint_{\partial R}\mathbf F\cdot\mathbf n\,\mathrm dS=\iiint_R\nabla\cdot\mathbf F\,\mathrm dV

(where \mathbf n denotes the unit normal vector to \partial R, but we don't need to worry about it now)

We have

\mathrm{div }\mathbf F=(\nabla\cdot\mathbf F)(x,y,z)=\dfrac{\partial\mathbf F}{\partial x}+\dfrac{\partial\mathbf F}{\partial y}+\dfrac{\partial\mathbf F}{\partial z}
\nabla\cdot\mathbf F=3x^2+3y^2+3z^2

For the solid R with boundary \partial R, we can set up the following volume integral in cylindrical coordinates for ease:

\displaystyle3\iiint_R(x^2+y^2+z^2)\,\mathrm dV=3\int_{z=0}^{z=4}\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=2}(r^2+z^2)r\,\mathrm dr\,\mathrm d\theta\,\mathrm dz
=\displaystyle6\pi\int_{z=0}^{z=4}\int_{r=0}^{r=2}(r^3+rz^2)\,\mathrm dr\,\mathrm dz
=\displaystyle12\pi\int_{z=0}^{z=4}(2+z^2)\,\mathrm dz
=352\pi
5 0
3 years ago
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