Number 7:
answer: a) odd
b) negative
explanation: let’s look at end behaviour. we know that all odd degree polynomials have opposite end behaviours, meaning that as x approaches negative infinity it will be in an opposite quadrant compared to when x is approaching positive infinity. Since x starts in Quad 2 and ends in Quad 4, we know it’s odd degree!! To figure out whether the leading coefficient is positive or negative, let’s look at what we already know about functions. Any odd function that has a positive leading coefficient will go from Quad 1 to Quad 3. Think about y = x^3 for example. Since this function goes from 2 to 4, the L.C. is negative.
number 8:
answer: a) even
b) negative
explanation: same logic as above but with even degree functions. Think about y = x^2 or x^4
Answer:
x = (2 i π n)/log(4) + log(2 sqrt(2))/log(4) for n element Z
Step-by-step explanation:
Solve for x:
2 sqrt(2) = 4^x
Hint: | Reverse the equality in 2 sqrt(2) = 4^x in order to isolate x to the left hand side.
2 sqrt(2) = 4^x is equivalent to 4^x = 2 sqrt(2):
4^x = 2 sqrt(2)
Hint: | Eliminate the exponential from the left hand side.
Take the logarithm base 4 of both sides:
Answer:x = (2 i π n)/log(4) + log(2 sqrt(2))/log(4) for n element Z
Answer:
-1.5
Step-by-step explanation:
-1 1/4 + 3/4= -0.5
-0.5-1= -1.5
Answer:
1/3 and 10/11, or 9/27 and 40/44
Step-by-step explanation:
Simplified 3/9 by 3.
Simplified 20/22 by 2.
