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Vanyuwa [196]
3 years ago
6

∜64= 4ˣ, what is the value of x?

Mathematics
1 answer:
svlad2 [7]3 years ago
8 0

Answer:

x = (2 i π n)/log(4) + log(2 sqrt(2))/log(4) for n element Z

Step-by-step explanation:

Solve for x:

2 sqrt(2) = 4^x

Hint: | Reverse the equality in 2 sqrt(2) = 4^x in order to isolate x to the left hand side.

2 sqrt(2) = 4^x is equivalent to 4^x = 2 sqrt(2):

4^x = 2 sqrt(2)

Hint: | Eliminate the exponential from the left hand side.

Take the logarithm base 4 of both sides:

Answer:x = (2 i π n)/log(4) + log(2 sqrt(2))/log(4) for n element Z

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