What x^2 x 3x + 1000x please help

A particle travels along the x-axis such that its velocity is given by v(t) = (t^0.7 + 4t) cos (t^2). What is the average accele

Airida [17]

It's not clear to me what the given interval is supposed to be, so I'll use a generic one, [a, b] with a < b.

The average acceleration of the particle over this interval is given by the average rate of change of v(t),

$a_{\rm ave} = \dfrac{v(b) - v(a)}{b - a} = \boxed{\dfrac{(b^{0.7}+4b)\cos(b^2) - (a^{0.7}+4a)\cos(a^2)}{b - a}}$

8 0

2 years ago

An advertisement for a popular weight-loss clinic suggests that participants in its new diet program lose, on average, more than

Sedbober [7]

Testing the hypothesis, it is found that:

a)

The null hypothesis is: $H_0: \mu \leq 10$

The alternative hypothesis is: $H_1: \mu > 10$

b)

The critical value is: $t_c = 1.74$

The decision rule is:

If t < 1.74, we do not reject the null hypothesis.
If t > 1.74, we reject the null hypothesis.

c)

Since t = 1.41 < 1.74, we do not reject the null hypothesis, that is, it cannot be concluded that the mean weight loss is of more than 10 pounds.

Item a:

At the null hypothesis, it is tested if the mean loss is of at most 10 pounds, that is:

$H_0: \mu \leq 10$

At the alternative hypothesis, it is tested if the mean loss is of more than 10 pounds, that is:

$H_1: \mu > 10$

Item b:

We are having a right-tailed test, as we are testing if the mean is more than a value, with a significance level of 0.05 and 18 - 1 = 17 df.

Hence, using a calculator for the t-distribution, the critical value is: $t_c = 1.74$ .

Hence, the decision rule is:

If t < 1.74, we do not reject the null hypothesis.
If t > 1.74, we reject the null hypothesis.

Item c:

We have the standard deviation for the sample, hence the t-distribution is used. The test statistic is given by:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.
$\mu$ is the value tested at the null hypothesis.
s is the standard deviation of the sample.
n is the sample size.

For this problem, we have that:

$\overline{x} = 10.8, \mu = 10, s = 2.4, n = 18$

Thus, the value of the test statistic is:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{10.8 - 10}{\frac{2.4}{\sqrt{18}}}$

$t = 1.41$

Since t = 1.41 < 1.74, we do not reject the null hypothesis, that is, it cannot be concluded that the mean weight loss is of more than 10 pounds.

A similar problem is given at brainly.com/question/25147864

3 0

2 years ago

The rise and span for a roof are shown. The pitch of a roof is the ratio of the rise to the half-span. If the rise is 8 feet and

Effectus [21]

Half-span is half of span. Pitch of the roof is calculated as rise/(span/2). In this case, rise is 8 feet and span is 30 feet. So, the pitch can be calculated as 8/(30/2) or 8/15. Pitch is normally represented as the number of inches of rise per foot. So, to reduce 8/15 to match a foot, we multiply it by 12. So, (8/15) * 12 gives us 6.4 inches of rise per foot.

3 0

3 years ago

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Convert the decimal 0.8034 to a fraction and classify it as either rational or irrational.

Llana [10]

Answer:

Fractional form of 0.8034 $=\frac{4017}{5000}$

Since 4017 and 5000 are whole numbers this fraction is rational.

Step-by-step explanation:

We have $0.8034=\frac{8034}{10000} =\frac{4017}{5000}$

Fractional form of 0.8034 $=\frac{4017}{5000}$

Since 4017 and 5000 are whole numbers this fraction is rational.

7 0

3 years ago

What is |-8| ? -16

olga nikolaevna [1]

Answer:

8

Those little "sticks" are called absolute value.

For example, the absolute value of 2 is 2, and the absolute value of −2 is also 2. The absolute value of a number may be thought of as its distance from zero along real number line.

Thus, it doesn't matter if the number is positive or negative. As it only counts its distance from 0, on the number line.

I hope it helps.

5 0

2 years ago

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