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4 years ago

Enter the equations of the asymptotes for the function f(x). f(x)= 3/x−7 + 2

Mathematics

1 answer:

Alexxx [7]4 years ago

3 0

Answer:

x = 7, y = 2

Step-by-step explanation:

I assume it is 3/(x-7) + 2.

When x = 7, there is an asymptote because it is undefined.

When y = 2, there is also one, because 3/(x-7) is never 0.

These are the only ones.

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3 years ago

If you invest $100,000 in an account earning 8% interest compounded annually, how long will it take until the account holds $300

Monica [59]

We have been given that you invest $100,000 in an account earning 8% interest compounded annually. We are asked to find the time it will take the amount to reach $300,000.

We will use compound interest formula to solve our given problem.

$A=P(1+\frac{r}{n})^{nt}$ , where,

A = Final amount after t years,

P = Principal amount,

r = Annual interest rate in decimal form,

n = Number of times interest is compounded per year,

t = Time in years.

$8\%=\frac{8}{100}=0.08$

$300,000=100,000(1+\frac{0.08}{1})^{1\cdot t}$

$300,000=100,000(1.08)^{t}$

$\frac{300,000}{100,000}=\frac{100,000(1.08)^{t}}{100,000}$

$3=(1.08)^{t}$

$(1.08)^{t}=3$

Let us take natural log on both sides of equation.

$\text{ln}((1.08)^{t})=\text{ln}(3)$

Using natural log property $\text{ln}(a^b)=b\cdot \text{ln}(a)$ , we will get:

$t\cdot \text{ln}(1.08)=\text{ln}(3)$

$\frac{t\cdot \text{ln}(1.08)}{\text{ln}(1.08)}=\frac{\text{ln}(3)}{\text{ln}(1.08)}$

$t=\frac{1.0986122886681097}{0.0769610411361283}$

$t=14.274914586$

Upon rounding to nearest tenth of year, we will get:

$t\approx 14.3$

Therefore, it will take approximately 14.3 years until the account holds $300,000.

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Answer: (2, 0)

Step-by-step explanation:

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timofeeve [1]

Answer is 68x bud thanks for lettting me ANWSER

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