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3 years ago

Enter the equations of the asymptotes for the function f(x). f(x)= 3/x−7 + 2

Mathematics

1 answer:

Alexxx [7]3 years ago

3 0

Answer:

x = 7, y = 2

Step-by-step explanation:

I assume it is 3/(x-7) + 2.

When x = 7, there is an asymptote because it is undefined.

When y = 2, there is also one, because 3/(x-7) is never 0.

These are the only ones.

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Given:

The given expression is $(2^3)(2^{-4})$

We need to determine how the expression can be simplified.

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Let us determine how the expression can be simplified.

The expression is given by

$(2^3)(2^{-4})$

Applying the exponent rule that $a^{b} \cdot a^{c}=a^{b+c}$ in the above expression, we get;

$2^{3} \cdot 2^{-4}=2^{3-4}$

Adding the exponents, we get;

$2^{3} \cdot 2^{-4}=2^{-1}$

Again, applying the exponent rule $a^{-1}=\frac{1}{a}$ , we get;

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3 years ago

What percent of 250 is 100?

mr_godi [17]

Answer:

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