The surface area of the triangular prism is 93 squared feet.
<h3>What is the
surface area of the
triangular prism?</h3>
The surface area of triangular prism is expressed as;
S.A = bh + ( s₁ + s₂ + s₃ )H
From the diagram;
- h = 2ft
- b or s₁ = 3ft
- s₂ = 3ft
- s₃ = 3ft
- H = 10ft
We substitute our given values into the equation above.
S.A = bh + ( s₁ + s₂ + s₃ )H
S.A = (3ft × 2ft) + ( 3ft + 3ft + 3ft )10ft
S.A = 3ft² + ( 9ft )10ft
S.A = 3ft² + 90ft²
S.A = 93ft²
The surface area of the triangular prism is 93 squared feet.
Learn more about prisms here: brainly.com/question/21079821
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Answer:
26
Step-by-step explanation:
Pythagorean Theorem and Radius used
24^2 + 10^2 = 676
8,887 cans divided by 27 classrooms is 329.1481 so each class donated about
329 cans
(a^4 + 4b^4) ÷ (a^2 - 2ab + 2b^2)
= [(a^2 - 2ab + 2b^2) (a^2 + 2ab + 2b^2)] / (a^2 - 2ab + 2b^2)
= a^2+2ab+2b^2 =The answer
(a + b)^2 = a^2 + 2ab + b^2 => square of sums
(a - b)^2 = a^2 - 2ab + b^2 => square of deference
and of course one of most important ones:
a^2 - b^2 = (a - b)(a + b) => difference of squares
Best Answer: (a^4 + 4b^4) ÷ (a^2 - 2ab + 2b^2)
= [(a^2 - 2ab + 2b^2) (a^2 + 2ab + 2b^2)] / (a^2 - 2ab + 2b^2)
= a^2 + 2ab + 2b^2
a^4 + 4b^4 => i.e. 4a^2b^2 ,
a^4 + 4a^2b^2 + 4b^4 => a^2 + 2ab + b^2 = (a + b)^2, if : a = a^2 , b = 2b^2:
(a^2 + 2b^2)^2 = a^4 + 4a^2b^2 + 4b^4 => We can't add or subtract the value to the expression.
a^4 + 4a^2b^2 + 4b^4 - 4a^2b^2 =>
(a^2 + 2b^2)^2 - 4a^2b^2 =>
(a^2 + 2b^2 - 2ab)(a^2 + 2b^2 + 2ab) =>
(a^2 - 2ab + 2b^2) (a^2 + 2ab + 2b^2)
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