Question

Sean b= 5,79; c= 10,4,el angulo A= 54,46°, el angulo C mide ?

Answer 1

Answer:

$C \approx 91.732^{\circ}$

Step-by-step explanation:

(This exercise is presented in Spanish and for that reason explanation will be held in such language)

El lado restante se determina por la Ley del Coseno:

$a = \sqrt{b^{2}+c^{2}-2\cdot b\cdot c \cdot \cos A}$

$a = \sqrt{5.79^{2}+10.4^{2}-2\cdot (5.79)\cdot (10.4)\cdot \cos 54.46^{\circ}}$

$a \approx 8.466$

Finalmente, el angulo C se halla por medio de la misma ley:

$\cos C = - \frac{c^{2}-a^{2}-b^{2}}{2\cdot a \cdot b}$

$\cos C = -\frac{10.4^{2}-8.466^{2}-5.79^{2}}{2\cdot (8.466)\cdot (5.79)}$

$\cos C = -0.030$

$C \approx 91.732^{\circ}$