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irakobra [83]
3 years ago
15

Help me please -4.5+4.4+_____=0

Mathematics
1 answer:
s2008m [1.1K]3 years ago
4 0

Answer:

+0.1

Step-by-step explanation:

Note that -4.5 + 4.4 = -0.1.

Adding 0.1 to -0.1 results in 0.

The unknown was +0.1.

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I will mark you brainiest if you can answer this, please help
Marina86 [1]

Answer:

Divide

Step-by-step explanation:

Divide everything on both sides of the equal sign by the coefficient to get rid of it. This only works in this example.

Please Brainliest

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7 0
2 years ago
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12. Determine the area of the shaded region. 12 in 12 in​
vekshin1

Answer:

  • 216/7 in²

Step-by-step explanation:

<u>We know that:</u>

  • Area of shaded region = Area of square - Area of circles
  • Radius of circle = 3 in
  • Area of circle = πr²
  • Area of square = s²

<u>Solution:</u>

  • Area of shaded region = Area of square - Area of circles
  • => Area of shaded region = (12²) - 4(22/7 x 3 x 3)
  • => Area of shaded region = (144) - 4(22/7 x 9)
  • => Area of shaded region = (144) - 4(198/7)
  • => Area of shaded region = 144 - 792/7
  • => Area of shaded region = 144 x 7/7 - 792/7
  • => Area of shaded region = 1008/7 - 792/7
  • => Area of shaded region = 1008/7 - 792/7
  • => Area of shaded region = 216/7 in²
3 0
2 years ago
The number of cars at a dealership dropped from 64 to 48 after a weekend sale.
Mariana [72]

Answer:

25%

Step-by-step explanation:

{(whole- part)/whole}*100%

(64 -48)/64 *100%= 25%

8 0
3 years ago
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What is the nth term?
kumpel [21]

Let a_k denote the <em>k</em>th term of the sequence. Then

a_k=a_1+d(k-1)

where <em>d</em> is the common difference between consecutive terms in the sequence and <em>a</em>₁ is the first term.

The sum of the first <em>n</em> terms is

S_n=\displaystyle\sum_{k=1}^na_k=a_1+a_2+\cdots+a_{n-1}+a_n

From the formula for a_k, we get

S_n=\displaystyle\sum_{k=1}^n(a_1+d(k-1))=a_1\sum_{k=1}^n1+d\sum_{k=1}^n(k-1)

S_n=\displaystyle na_1+d\sum_{k=0}^{n-1}k

S_n=na_1+\dfrac{d(n-1)n}2

S_n=\dfrac n2(2a_1-d+dn)

So we have d=-5, and 2a_1-d=16 so that a_1=\frac{11}2.

Then the <em>n</em>th term in the sequence is

a_n=\dfrac{11}2-5(n-1)=\boxed{\dfrac{21-10n}2}

7 0
3 years ago
What are two consecutive integers whose sum is -97
zimovet [89]

Answer:

-48 and -49

Step-by-step explanation:

n + n + 1 = -97

2n + 1 = -97

2n + 1 - 1 = -97 - 1

2n = -98

2n/2 = -98/2

n = -49

 -49 + 1 = -48

 -49, -48

8 0
3 years ago
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