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3 years ago

Solve x+1/3 =x-2/4+1/3

Mathematics

1 answer:

Vinvika [58]3 years ago

5 0

Answer:

No solution.

Step-by-step explanation:

x+1/3 =x-2/4+1/3

Subtract x and 1/3 on both sides.

x-x=-2/4

0= - 1/2

There are no solutions.

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Aaron works as a bar attendant and receives $11 per hour. On Saturday he works for five hours at normal time and three hours ove

scoundrel [369]

Answer:

so his total pay for Saturday would be $104.50

Step-by-step explanation:

He works 5 hours at $11 per hour which gets a total of 55$

He also works 3 hours of overtime where he gets payed 1.5x pay

11 x 1.5 = 16.5 (10x1.5 = 15 1x1.5 = 1.5)

so he gets $16.5 per hour for 3 hours which = 49.5$

49.5 + 55 = $104.50

5 0

3 years ago

Is d= -12 a solution to the equation 8d+6= -8d-186

kupik [55]

Answer:

It is a solution

Step-by-step explanation:

8d+6= -8d-186

Add 8d to each side

8d+8d+6= -8d+8d-186

16d +6 = -186

Subtract 6 from each side

16d +6-6 = -186 -6

16d = -192

Divide each side by 16

16d/16 = -192/16

d = -12

8 0

3 years ago

After a dilation with center (0,0) the image of DB is D’B’ if DB=6 and D’B’=2 the scale factor of dilation is what ?

bezimeni [28]

Answer:

scale factor = $\frac{1}{3}$

Step-by-step explanation:

the scale factor is the ratio of corrresponding sides. image to original.

scale factor = $\frac{D'B'}{DB}$ = $\frac{2}{6}$ = $\frac{1}{3}$

7 0

3 years ago

Plz help! Is this right? Question is below!

GalinKa [24]

Answer:

infinitely many solutions

Step-by-step explanation:

8 0

4 years ago

Read 2 more answers

Find cos(2*ABC) 100POINTS

juin [17]

Answer:

$-\dfrac{7}{25}$

Step-by-step explanation:

<u>Trigonometric Identities</u>

$\cos(A \pm B)=\cos A \cos B \mp \sin A \sin B$

<u>Trigonometric ratios</u>

$\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}\quad\tan(\theta)=\dfrac{O}{A}$

where:

$\theta$ is the angle
O is the side opposite the angle
A is the side adjacent the angle
H is the hypotenuse (the side opposite the right angle)

Using the trig ratio formulas for cosine and sine:

$\cos(\angle ABC)=\dfrac{3}{5}$

$\sin(\angle ABC)=\dfrac{4}{5}$

Therefore, using the trig identities and ratios:

$\begin{aligned}\implies \cos(2 \cdot \angle ABC) & = \cos(\angle ABC + \angle ABC)\\\\& = \cos (\angle ABC) \cos (\angle ABC) - \sin(\angle ABC) \sin (\angle ABC)\\\\& = \cos^2(\angle ABC)-\sin^2(\angle ABC)\\\\& = \left(\dfrac{3}{5}\right)^2-\left(\dfrac{4}{5}\right)^2\\\\& = \dfrac{3^2}{5^2}-\dfrac{4^2}{5^2}\\\\& = \dfrac{9}{25}-\dfrac{16}{25}\\\\& = \dfrac{9-16}{25}\\\\& = -\dfrac{7}{25} \end{aligned}$

7 0

2 years ago

Read 2 more answers

Solve x+1/3 =x-2/4+1/3​

Solve x+1/3 =x-2/4+1/3