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Anit [1.1K]
3 years ago
13

How do I figure the equation out

Mathematics
1 answer:
Tatiana [17]3 years ago
4 0

Answer:

<em><u>Answer for Parallel line:</u></em> y = 3x - 13

<em><u>Answer for Perpendicular line: </u></em>y = (-1/3)x +17/3

Step-by-step explanation:

<em><u>Parallel line</u></em>

For the slope of a line parallel to another (given) line, just read the slope of the given line. It (in this case) is the coefficient in front of the x.

m = 3

So far what you have is y = 3x + b

To find b, use the given point (2,5)

x = 2

y = 5  Substitute these values into the skeletal equation. y = 3x + b

2 = 3*5 + b     Subtract 15 from both sides.

2 = 15 + b

2 - 15 = b switch sides

b = - 13

Answer y = 3x - 13

Part B

<em><u>Perpendicular line</u></em>

The perpendicular line will have a slope determined by the following formula

m1 * m2 = - 1

m1 is the slope of the given line which is 3

3 * m2 = - 1

m2 = - 1/3

So far, what you have is

y = (-1/3)x + b To find b, use the same 2 givens as above.

y = 5

x = 2

Substitute into the skeletal equation.

5 = (-1/3)(2) + b

5 = -2/3  + b  Switch sides.  

b - 2/3 = 5  Add 2/3 to both sides.

b = 5 + 2/3

b = 5 2/3 = 17 / 3

Answer

y = (-1/3)x + 17/3

If this doesn't seem right, and you have choices, could you please list them?

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kirza4 [7]
For your question the answer is C.

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3 years ago
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In a certain Algebra 2 class of 30 students, 19 of them play basketball and 12 of them play baseball. There are 8 students who p
Alenkinab [10]

Answer:

Probability that a student chosen randomly from the class plays basketball or baseball is  \frac{23}{30} or 0.76

Step-by-step explanation:

Given:

Total number of students in the class = 30

Number of students who plays basket ball = 19

Number of students who plays base ball = 12

Number of students who plays base both the games = 8

To find:

Probability that a student chosen randomly from the class plays basketball or baseball=?

Solution:

P(A \cup B)=P(A)+P(B)-P(A \cap B)---------------(1)

where

P(A) = Probability of choosing  a student playing basket ball

P(B) =  Probability of choosing  a student playing base ball

P(A \cap B) =  Probability of choosing  a student playing both the games

<u>Finding  P(A)</u>

P(A) = \frac{\text { Number of students playing basket ball }}{\text{Total number of students}}

P(A) = \frac{19}{30}--------------------------(2)

<u>Finding  P(B)</u>

P(B) = \frac{\text { Number of students playing baseball }}{\text{Total number of students}}

P(B) = \frac{12}{30}---------------------------(3)

<u>Finding P(A \cap B)</u>

P(A) = \frac{\text { Number of students playing both games }}{\text{Total number of students}}

P(A) = \frac{8}{30}-----------------------------(4)

Now substituting (2), (3) , (4) in (1), we get

P(A \cup B)= \frac{19}{30} + \frac{12}{30} -\frac{8}{30}

P(A \cup B)= \frac{31}{30} -\frac{8}{30}

P(A \cup B)= \frac{23}{30}

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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