Function 1 has a maximum at y = 1
Now we need to find the maximum of Function 2 by completing the square:
-x^2 + 2x - 3
= -(x^2 - 2x) - 3
= -(x - 1)^2 +1 - 3
= -(x - 1)^2 - 2
Therefor the turning point is at (1, -2) and the maximum is at y = -2
-2 < 1, therefor Function 1 has the larger maximum
Answer:
I am in for the game......
Answer:
m=-1/4
Step-by-step explanation:
The answer is 3 hope this helps
Step-by-step explanation:
Using synthetic division of polynomials 3x⁴-2x²+4x+9÷x+2. Rewrite the dividend as 3x⁴+0x³-2x²+4x+9
2 | 3 0 -2 4 9
| 6 -12 20 -32
3 -6 10 -16 41
So the quotient is 3x³-6x²+10x-16 with a remainder of 41
Therefore, 3x³-6x²+10x-16+(41/x+2)
