Work done = 100J
Distance = 5 meters
Force = ?
Force = 100/5 = 20N
Therefore, the force needed is 20 Newtons
Unlike nonsteroid hormones, steroid hormones
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Work done = 100J
Distance = 5 meters
Force = ?
Force = 100/5 = 20N
Therefore, the force needed is 20 Newtons
<h2>Frequency of allele </h2>
Explanation:
Hardy Weinberg Equilibrium is used to calculate the allelic as well as genotypic frequency
Allelic frequency of dominant and recessive allele is represented by p and q respectively whereas genotypic frequency of dominant genotype is represented by and
respectively
Given:
H allele (p) = hairy heffalump (dominant)
h allele (q) = hairless heffalump (recessive)
36% of heffalump population is hairless represents the % of recessive genotype, hh () =36%
Calculation of frequency of the h allele (q) :
Frequency of genotype hh () will be: 36/100=0.36 or 0.6*0.6
Frequency of h allele (q) will be 0.6