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Serjik [45]
3 years ago
5

A store gives away gift bags during a sale. Of these gift bags, 50% are green, 20% are yellow, and 30% are blue. The average num

ber of items in each green bag is 8. The average number of items in each yellow bag is 5. The average number of items in each blue bag is 8. What is the average number of items in all the gift bags? PLS, HELP WILL GIVE YOU 95 PTS!!!!!!!!
Mathematics
1 answer:
Dmitrij [34]3 years ago
4 0

Answer:

7

Step-by-step explanation:

So I started with an equation (g for green variable, y for yellow variable, b for blue variable)

8g + 5y + 8b = ??

Because of the lack of variables, I'm not really sure how to tie in the 50%, 20%, and 30%. (It could be unnecessary information)

But going off the average number of items, you have 8 green, 5 yellow, and 8 blue. So you can add them together for 21. From here, you divide 21 by 3 to get your average, 7.

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Bob drove from home to work at 75 mph.After work the traffic was heavier,and he drove home at 40 mph.His driving time to and fro
Ilya [14]

Answer:

Bob drove from home to work at 75 mph. After work the traffic was heavier, and he drove home at 40 mph. His driving time to and from work was 1 hour and 9 minutes. How far does he live from his job?

=================

Avg speed for the round trip = 2*75*40/(75+40) = 6000/115 = 1200/23 mi/hr

RT distance = 1200/23 * 69 minutes * 1 hr/60 mins =

= 60 miles

30 miles each way

Step-by-step explanation:

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3 years ago
A new oven is $1,500. the sales tax is 6.2%. what is the total cost of the oven including sales tax.
DIA [1.3K]

Answer:

B

Step-by-step explanation:

5 0
3 years ago
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9•(-5)<br><br> A. -45<br> B. -95<br> C. 4<br> D. 45
alexgriva [62]

Answer:

A. -45

Step-by-step explanation:

multiplying a positive an a negative number gives out a negative result

so when we multiple 9 with -5 the result is -45

3 0
3 years ago
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Nikolay [14]

Replace x with π/2 - x to get the equivalent integral

\displaystyle \int_{-\frac\pi2}^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx

but the integrand is even, so this is really just

\displaystyle 2 \int_0^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx

Substitute x = 1/2 arccot(u/2), which transforms the integral to

\displaystyle 2 \int_{-\infty}^\infty \frac{\cos(u)}{u^2+4} \, du

There are lots of ways to compute this. What I did was to consider the complex contour integral

\displaystyle \int_\gamma \frac{e^{iz}}{z^2+4} \, dz

where γ is a semicircle in the complex plane with its diameter joining (-R, 0) and (R, 0) on the real axis. A bound for the integral over the arc of the circle is estimated to be

\displaystyle \left|\int_{z=Re^{i0}}^{z=Re^{i\pi}} f(z) \, dz\right| \le \frac{\pi R}{|R^2-4|}

which vanishes as R goes to ∞. Then by the residue theorem, we have in the limit

\displaystyle \int_{-\infty}^\infty \frac{\cos(x)}{x^2+4} \, dx = 2\pi i {} \mathrm{Res}\left(\frac{e^{iz}}{z^2+4},z=2i\right) = \frac\pi{2e^2}

and it follows that

\displaystyle \int_0^\pi \cos(\cot(x)-\tan(x)) \, dx = \boxed{\frac\pi{e^2}}

7 0
2 years ago
The histogram displays how many students are in each classroom during homeroom. What percentage of classrooms have 25 students o
Lelechka [254]

Answer:

its 40% but since it's not there it could be 45%

Step-by-step explanation:

hope this helps

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3 years ago
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