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Tcecarenko [31]
3 years ago
9

A team of 6 people is to be chosen from 8 men and 6 women. Find the number of different teams that may be chosen if

Mathematics
1 answer:
kherson [118]3 years ago
5 0

9514 1404 393

Answer:

  a) 3003

  b) 1419

Step-by-step explanation:

a) With no restrictions, the problem amounts to counting the number of combinations of 14 people taken 6 at a time. That is ...

  14!/(6!(14-6)!) = 3003 . . . teams with no restrictions

__

b) With the restrictions, there are two cases:

  (i) all 6 people are taken from the 12 that exclude the couple. That number of combinations is ...

  12!/(6!(12-6)!) = 924

  (ii) 4 people are taken from the 12 that exclude the couple, and the couple fills the last two team slots. That number is ...

  12!/(4!(12-4)!) = 495

The sum of the counts of these two cases is ...

  924 +495 = 1419 . . . teams with inseparable couple

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vfiekz [6]
Since 270=262+8, and \dfrac{270}9=30, we have

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so the answer is A.

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3 years ago
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3 years ago
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erastovalidia [21]

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